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andreev551 [17]
3 years ago
7

It takes Ryan 1/5 hour to bike home from school. his biking speed is 10 mph

Mathematics
1 answer:
Anika [276]3 years ago
5 0
1/50? I can’t be sure....

Ok, so.. first you write both the problems down and write the 10 as a fraction (so it would automatically be 10/1). Then invert so it would be a multiplication problem (1/5 x 1/10). Since you can’t cross cancel, you multiply across. So, 1/5 x 1/10 (1 x 1 and 10 x 5)
1/50
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The number A of tablet computers sold (in millions) can be modeled by the function A=4.5t2+43.5t+17 , where t represents the num
Rina8888 [55]
The problem indicates that A represents the number of tablet computers sold in millions. So, if 65 million were sold, we must substitute A = 65 to the equation. Then, we find for t.

65 = 4.5t² +43.5t + 17
Solving for t using a calculator,
t = 1 and -10.67

Let's take the positive root. So, t=1.
That means the year would be 1 year after 2010. <em>Therefore, the answer is 2011.</em>
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3 years ago
Can someone please explain this
Pani-rosa [81]

Answer:

x = 7

Step-by-step explanation:

There is a total of 180 degrees in a triangle. To solve you add the other angles and set = to 180 then solve for x

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172 = 33 + 90 + 7x

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The empty gas tank of a motor boat is to be filled. The tank is shaped like a rectangular prism with length 20 cm, width
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3 years ago
A system of equations has 1 solution. If 4x - y = 5 is one of the equations, which could be the other equation?
Lera25 [3.4K]
4x - y = 5 is an verb like 4 - 5
4 0
3 years ago
In this problem we will be dealing with the probability density function (pdf) associated with a continuous random variable, X.
konstantin123 [22]

Answer:

b)\ 0.568

Step-by-step explanation:

Given

f(x) = 6x(1- x);\ 0 \le x \le 1

Required

P(0.3 < x < 0.7)

From the question, we have:

P(a < x < b) = \int\limits^b_a {f(x)} \, dx

So, we have:

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x(1 - x)} \, dx

Open bracket

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x - 6x^2} \, dx

Integrate

P(0.3 < x < 0.7) =  \frac{6x^2}{2} - \frac{6x^3}{3}}|\limits^{0.7}_{0.3}

P(0.3 < x < 0.7) =  3x^2 - 2x^3|\limits^{0.7}_{0.3}

Substitute 0.7 and 0.3 for x

P(0.3 < x < 0.7) =  (3*0.7^2 - 2*0.7^3) - (3*0.3^2 - 2*0.3^3)

Using a calculator, we have:

P(0.3 < x < 0.7) =  (0.784) - (0.216)

Remove brackets

P(0.3 < x < 0.7) =  0.784 - 0.216

P(0.3 < x < 0.7) =  0.568

3 0
2 years ago
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