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liraira [26]
2 years ago
15

F'(-7, 13) was dilated by a scale factor of 2 about (-2, -5), the resulting image is___

Mathematics
1 answer:
AveGali [126]2 years ago
3 0

The resulting image of the point F(x, y) = (- 7, 13) is F'(x, y) = (- 12, 31).

<h3>What is the resulting image of a point by rigid transformation?</h3>

In this problem we have a point that has to be transformed by a kind of rigid transform known as dilation, which is defined by the following equation:

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]             (1)

Where:

  • O(x, y) - Center of dilation
  • P(x, y) - Original point
  • P'(x, y) - Image
  • k - Scale factor

If we know that O(x, y) = (- 2, - 5), F(x, y) = (- 7, 13) and k = 2, then the resulting image is:

F'(x, y) = (- 2, - 5) + 2 · [(- 7, 13) - (- 2, - 5)]

F'(x, y) = (- 2, - 5) + 2 · (- 5, 18)

F'(x, y) = (- 2, - 5) + (- 10, 36)

F'(x, y) = (- 12, 31)

The resulting image of the point F(x, y) = (- 7, 13) is F'(x, y) = (- 12, 31).

To learn more on rigid transformations: brainly.com/question/28004150

#SPJ1

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Answer:

Step-by-step explanation:

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To prove: Circle O is similar to circle X.

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A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.

The scale factor x to increase X:

⇒

A translation followed by a dilation with scale factor  will map one circle to the other, thus proving the given both circles similar.

Therefore, circle O is similar to circle X.

Step-by-step explanation:

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3 years ago
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tankabanditka [31]

Answer:

A. 23/24

Hope this helped

Step-by-step explanation:

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3 years ago
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andrew-mc [135]

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3 0
2 years ago
Help! Algebra!!!
balandron [24]
Thet contradict each other, that's why both of them are incorrect.
<span>Suppose that a polynomial has four roots: s, t, u, and v. If the polynomial were evaluated at any of these values, it would have to be zero. Therefore, the polynomial can be written in this form. 

p(x)(x - s)(x - t)(x - u)(x - v), where p(x) is some non-zero polynomial 

This polynomial has a degree of at least 4. It therefore cannot be cubic. 

Now prove Kelsey correct. We have already proved that there can be no more than three roots. To prove that a cubic polynomial with three roots is possible, all we have to do is offer a single example of that. This one will do. 

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4 0
3 years ago
In this truss bridge, AAOB ABDC. AO=5 meters, BD=10 meters, AB=5 meters. What is the length of BC? A. 5 m B. 8 m C. 10 m D. 15 m
Olenka [21]

Consider \Delta AOB\cong \Delta BDC.

Given:

\Delta AOB\cong \Delta BDC, AO=5\ m,BD=10\ m, AB=5\ m.

To find:

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We have,

\Delta AOB\cong \Delta BDC

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5\ m=BC

The length of BC is 5 m. Therefore, the correct option is A.

5 0
2 years ago
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