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patriot [66]
3 years ago
13

Suppose that appearances of a foe to battle (that is, a random encounter) in a role-playing game occur according to a Poisson pr

ocess, and the average rate equals one appearance per two minutes. Measured in minutes, the time T until the next encounter is Exponential with what rate parameter?
Mathematics
1 answer:
Dimas [21]3 years ago
5 0

Answer:

Rate parameter of \mu = 0.5

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:  

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

One appearance per two minutes.

This means that m = 2

Measured in minutes, the time T until the next encounter is Exponential with what rate parameter?

\mu = \frac{1}{m} = \frac{1}{2} = 0.5

So

Rate parameter of \mu = 0.5

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Jared surf for one third of the nine hours he was at the beach he spent the rest of the time building a sandcastle how many hour
WINSTONCH [101]
9 dived by 3 = 3
so he surfed for 3 hours = 1/3 of 9
and there are 6 hours left 

so he spent 6 hours building a sandcastle 
8 0
3 years ago
Read 2 more answers
Mr.Sampson fills the family pool with water for the summer, after two hours, the water has reached the depth of 2.5 feet.After t
scoray [572]

This question is incomplete

Complete Question

Mr Sampson fills the family pool with water for the summer.After two hours,the water has reached a depth of 2.5 feet. After three hours,the water level has risen to 3 3/4 feet.If the relationship between time and water depth is proportional,what is the constant of proportionality?

Answer:

1.33

Step-by-step explanation:

Time is proportional to Depth

Hence:

T ∝ D

T = kD

Where k is the constant of proportionality

After two hours,the water has reached a depth of 2.5 feet. After three hours,the water level has risen to 3 3/4 feet.

Total number of hours now is 3 + 2 = 5 hours

5 = k × 3 3/4

5 = k × 3.75

k = 5/3.75

k = 1.33

8 0
3 years ago
2) Joanie got paid $111 to babysit three kids for 6 hours. How much was she paid per hour?
Hatshy [7]

Answer:

18.5

Step-by-step explanation:

Since she was paid $111 for 6 hours, you divide 111/6 to get 18.5

6 0
3 years ago
Hadley has 3/6 of a box of white envelopes and 1/3 of a box of gray envelopes. When full, each box of envelopes has the same num
QveST [7]

Answer:

<u>The two statements that apply are A and B.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

White envelopes Hadley has = 3/6 of a box

Gray envelopes Hadley has = 1/3 of a box

When full, each box of envelopes has the same number of envelopes

Hadley said she has 4/9 of a box when she puts the white envelopes and gray envelopes together.

2. Which statements describe this situation? Select the two statements that apply.

Let's add 3/6 and 1/3

3/6 + 1/3 = 3/6 + 2/6 = 5/6

A. Hadley’s answer is incorrect, because 3/6 is equal to 1/2 , and 4/9 is less then 1/2 .   This is correct.

B. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 5/6.   This is correct.

C. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 2/6.  This is wrong

D. Hadley's answer is correct, because 3 and 1 is 4, and 6 and 3 is 9. This is wrong.

<u>The two statements that apply are A and B.</u>

3 0
3 years ago
WILL MARK BRAINLIEST
dsp73
<h3>Refer to the diagram below</h3>
  1. Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
  2. Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
  3. Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
  4. Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
  5. Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.

Refer to the diagram below for examples of what I mean.

5 0
3 years ago
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