Question

Suppose that appearances of a foe to battle (that is, a random encounter) in a role-playing game occur according to a Poisson process, and the average rate equals one appearance per two minutes. Measured in minutes, the time T until the next encounter is Exponential with what rate parameter?

Answer 1

Answer:

Rate parameter of $\mu = 0.5$

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:  

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

One appearance per two minutes.

This means that $m = 2$

Measured in minutes, the time T until the next encounter is Exponential with what rate parameter?

$\mu = \frac{1}{m} = \frac{1}{2} = 0.5$

So

Rate parameter of $\mu = 0.5$