*question 2* I NEED HELP ASAPPPP
1 answer:
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9514 1404 393
Answer:
maximum height of 17.07 feet about 10.67 feet from the club
returns to the ground 21.33 feet away
Step-by-step explanation:
A graphing calculator can answer these questions easily.
The vertex of the quadratic ax²+bx+c is given by x=-b/(2a). For this quadratic function, the highest point is found at ...
x = -(3.2)/(2(-0.15)) = 32/3 = 10 2/3 . . . . feet horizontally from the club
The maximum height is the function value at that point.
h(10 2/3) = (-0.15(10 2/3) +3.2)(10 2/3) = 1.6(10 2/3) = 17 1/15
The ball reaches a maximum height of 17 1/15 feet at a horizontal distance of 10 2/3 feet from the club. The ball's flight is symmetrical about the peak, so it returns to the ground about 21 1/3 feet away.
