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kaheart [24]
3 years ago
9

Please Help Me answer this question

Mathematics
1 answer:
Paha777 [63]3 years ago
5 0
Please take a picture of the whole question :)
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Please help asap!!!look at the box
exis [7]
I think it’s B might be wrong though
5 0
3 years ago
Read 2 more answers
b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
4 years ago
Explain how u got ur answer pls
TiliK225 [7]

Answer:

The distributive property means that to multiply 3(x-4), you distribute the 3 by multiplying both x and -4 by 3. Therefore, the answer here is (3*x)+(3*-4), which is equal to 3x-12.

Hope this helps!

Step-by-step explanation:

5 0
2 years ago
What is the volume of a triangular pyramid that is 5 feet tall and has a base area of 9 square feet
igomit [66]

The volume of the triangular prism as described is; 15 cubic foot.

<h3>What is the volume of the triangular prism?</h3>

It follows from the formula for calculating the volume of a triangular prism that;

Volume = (1/3) × base area × height.

Consequently,

volume of the prism is; = (1/3) ×9 × 5

Volume = 15 cubic foot

Therefore, volume of the triangular prism as described is; 15 cubic foot.

Read more on triangular prism;

brainly.com/question/1284982

#SPJ1

6 0
2 years ago
What is the midpoint of the segment shown below? (-2,4) (6,-4)
tresset_1 [31]
<h2>solution :</h2>

let's assume the Coordinates be x and y

By using Section formula,

\boxed{ x =  (\dfrac{x_2 + x_1}{2} )}

  • x =   \dfrac{ - 2 + 6}{2}

  • x =  \dfrac{4}{2}

  • x = 2

____________________

\boxed {y =  (\dfrac{y_2 + y_1}{2} )}

  • \dfrac{ - 4 + 4}{2}

  • \dfrac{0}{4}

  • 0

____________________

\mathrm{Therefore \:\:the\:\: Coordinates\:\: of \:\:the\;\; mid-point\;\: of \;\;the\:\: given\:\: segment\:\; is}

\huge \boxed{(2,0)}

_____________________________

\mathrm{ \#TeeNForeveR} \: ☃

8 0
3 years ago
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