All categories

2 years ago

1/2 ÷8 = this on studyisland

Mathematics

2 answers:

vitfil [10]2 years ago

5 0

Answer:

0.19

Step-by-step explanation:

Vinil7 [7]2 years ago

5 0

Answer 1/16 or 0.0625
explanation just divide 1/2 by 8

You might be interested in

Can someone help me with this question? Thank you!

Natali [406]

Answer:

Step-by-step explanation:

22 is the largest number you are given in this diagram. 0 is the smallest. that would be your first step.

Next think about it as if you already know your midpoint, as in, midpoint being half of your ending value.

Lastly, you want to divide 22 in half, since midpoint is half of your line segment, and then answer you get is 11

3 0

3 years ago

the dog needs a 1/3 of a cup of dog food each day. the bag holds 5 cups of dog food how many days will it last ?

sleet_krkn [62]

Answer:

15 days

Step-by-step explanation:

You have 5 cups of food, and you give him 1/3 a day.

So, <em>5 divided by 1/3</em>, which would get you 15 days. Or you could cross-multiply, meaning you multiply across, but in this case I just made them line up so you can see how to do it. $(food)/(cupsperday) = 5/\frac{1}{3} \\OR\\\frac{(food)}{1}*(cupsperday) = \frac{5}{1} *\frac{3}{1}$

7 0

2 years ago

A standard dartboard has a diameter of 18 in. What is its area to the nearest square inch?

Reptile [31]

The meaning of the area is the measurement of a surface in this case a circle, which can be find by using the formula $A= \pi r^{2}$ , where r is equal to the radius of the circle.

In this exercise is given that the diameter of a standard cardboard is 18 inches or a radius of 9 inches and it is asked to find its area. Therefore, to find the area of the circle you should substitute the value of the radius into the previous mention formula.

$A= \pi r^{2}$
$A= \pi (9 in)^{2}$
$A= \pi (81 in^{2})$
$A=254.47 in^{2}$

The area of the standard dartboard is 254.47 square inches or 254 square inches.

8 0

2 years ago

Write a linear function with the values (-1,8) and (5,6)

valentina_108 [34]

Let the function be y = ax + c.

For (-1,8), 8 = a(-1) + c → 8 = - a + c

For (5,6), 6 = a(5) + c → 6 = 5a + c

Subtract one from abother,

2 = - 6a => - 1/3 = a

Hence, 8 = - 1/3 + c → 23/3 = c

Relation is:

y = (-1/3)x + (23/3)

3y = - x + 23

3y = 23 - x

8 0

3 years ago

Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)

marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

$~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill$

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}$

8 0

2 years ago