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timofeeve [1]
3 years ago
13

Part A:

Mathematics
2 answers:
shusha [124]3 years ago
8 0

Part A:

Six Tents Holds 42 People

Nine Tents Holds 63 People

10 Tents Holds 70 People

Part B:

Number of tents|||Number of people

1                          |||7

6                         |||42

9                         |||63

10                        |||70

Part C:

Tents=x

1x=7 people

Alenkinab [10]3 years ago
8 0

Answer:Part A:

6 tents: 42 people

9 tents: 63 people

10 tents: 70 people

Part B:

1 tent: 7 people

2 tents: 14 people

3 tents: 21 people

4 tents: 28 people

5 tents: 35 people

6 tents: 42 people

7 tents: 49 people

8 tents: 56 people

9 tents: 63 people

10 tents: 70 people

Part C:

1 tent = 7 people

So, each extra tent after 1 is gonna add 7.

Example:

1 tent = 7 people

2 tents = 14 people

3 tents = 21 people

4 tents = 28 people and so on.

Step-by-step explanation:

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Please help ill give brainliest if correct
yan [13]

Answer:

130

Step-by-step explanation:

ABC = 180 - 120 = 60

ACB = 180 - 70 - 60 = 50

ACD = 180 - 50 = 130

I hope I've helped you.

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2 years ago
HELP ME PLEASE!❤️ mathematics
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[19] x2 [38]x2[76]x2[152]x2[304] this is the answer

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3 years ago
Mrs. Hall records the height of 50 students in a spreadsheet the mean height is 60 inches after looking at the date again she re
iris [78.8K]
Answer is in a photo. i couldn’t attach it here, good luck!



6 0
3 years ago
Read 2 more answers
G(n-7) if g(x) =x^2-5/3x
Leno4ka [110]

Instead of x, we write n - 7 in the function equation

g(x)=x^2-\dfrac{5}{3}x\\\\g(n-7)=(n-7)^2-\dfrac{5}{3}(n-7)\\\\\text{use} (a-b)^2=a^2-2ab+b^2\\\text{and distributive property}\\\\=n^2-2(n)(7)+7^2+\left(-\dfrac{5}{3}\right)(n)+\left(-\dfrac{5}{3}\right)(-7)\\\\=n^2-14n+49-\dfrac{5}{3}n+\dfrac{35}{3}\\\\\text{combine like terms}\\\\=n^2+\left(-14n-1\dfrac{2}{3}n\right)+\left(49+11\dfrac{2}{3}\right)\\\\=n^2-15\dfrac{2}{3}n+60\dfrac{2}{3}

8 0
3 years ago
I need the angle measurements for each letter in this image
Blizzard [7]

Answer:

To find c you know that angles on a straight line equal 180° (supplementary angles). So 70+30+∠C=180.

Now we can solve this.

100+c=180.

Move the 100 over to the other side.

100-100+c=180-100

Simplify.

∠C=80°

Because we know that the two lines with double arrows are parallel, we can use the rule that alternate interior angles are congruent. This means that ∠E=70.

∠E=70°

Since the total sum of the angles in a triangle are equal to 180°, we know that ∠D+∠C+∠E=180. Because we already know ∠C and ∠E we can put those numbers in for them. 80°+70°+∠D=180°. Now we can solve this.

80+70+D=180

Simplify this.

150+D=180

Now we move the 150 over to the other side to get D by itself.

150-150+D=180-150

Simplify.

D=30

∠D=30°

Now we can find the vertical angle opposite ∠A by using the alternate interior angles rule again this time using the parallel lines with only one arrow on them. The vertical angle opposite ∠A=30°. Since vertical angles are congruent ∠A=30°.

∠A=30°

We are going to use the alternate angles rule one more time to solve for ∠B (this rule is very important when dealing with parallel lines), we could also use the corresponding angles rule but for simplicity we will just stick with the alternate angles rule. Because the vertical angle opposite ∠A is equal to 30°, we can see that the supplementary angle opposite ∠B=30°. Because this angle is supplementary with B we know that 30+B=180.Now we can solve this.

30+B=180

Now we move the 30 over to the other side.

30-30+B=180-30

Simplify.

B=150

∠B=150°

I hope this helps!

7 0
2 years ago
Read 2 more answers
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