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2 years ago

Part A:

Mathematics

2 answers:

shusha [124]2 years ago

8 0

Part A:

Six Tents Holds 42 People

Nine Tents Holds 63 People

10 Tents Holds 70 People

Part B:

Number of tents|||Number of people

1 |||7

6 |||42

9 |||63

10 |||70

Part C:

Tents=x

1x=7 people

Alenkinab [10]2 years ago

8 0

Answer:Part A:

6 tents: 42 people

9 tents: 63 people

10 tents: 70 people

Part B:

1 tent: 7 people

2 tents: 14 people

3 tents: 21 people

4 tents: 28 people

5 tents: 35 people

6 tents: 42 people

7 tents: 49 people

8 tents: 56 people

9 tents: 63 people

10 tents: 70 people

Part C:

1 tent = 7 people

So, each extra tent after 1 is gonna add 7.

Example:

1 tent = 7 people

2 tents = 14 people

3 tents = 21 people

4 tents = 28 people and so on.

Step-by-step explanation:

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Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?

Sveta_85 [38]

Complete Question:

Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ? For what values?(Make sure to use an inequality)

Answer:

y < 3

Step-by-step explanation:

The given two fractions are:

$\frac{7-2y}{6}$ and $\frac{3y-7}{12}$

We have to tell for which range of values is the value of first fraction larger than the second fraction. This can be done by setting up an inequality as shown:

$\frac{7-2y}{6} >\frac{3y-7}{12}$

The range of y which will satisfy this inequality will result in first fraction of larger value as compared to the second fraction.

Multiplying both sides of inequality by 12, we get:

$12 \times \frac{7-2y}{6} > 12 \times \frac{3y-7}{12} \\\\ 2(7-2y)>3y-7\\\\ 14-4y>3y-7\\\\ 14+7>3y+4y\\\\ 21>7y\\\\ 3>y\\\\ y$

This means, for y lesser than 3, the value of first fraction is larger than the second one.

3 0

2 years ago

Will someone please help me understand this?

mario62 [17]

Option A:

The length of diagonal JL is $3 \sqrt{5} \text { units }$ .

Solution:

In the quadrilateral, the coordinates of J is (1, 6) and L is (7, 3).

So that, $x_1=1, y_1=6, x_2=7, y_2=3$

To find the length of the diagonal JL.

Using distance formula:

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

$d=\sqrt{(3-6)^2+(7-1)^2}$

$d=\sqrt{(-3)^2+(6)^2}$

$d=\sqrt{9+36}$

$d=\sqrt{45}$

$d=\sqrt{3^2\times 5}$

$d=3\sqrt{ 5}$ units

The length of diagonal JL is $3 \sqrt{5} \text { units }$ .

Option A is the correct answer.

7 0

2 years ago

Read 2 more answers

Rewrite each algebraic expression with fewer terms. a. 9.5(a + 4) – a

alexdok [17]

Step-by-step explanation:

We distribute first:

(9.5*a)+(9.5*4)= 9.5a+38

We can subtract the a from 9.5a.

9.5a-a=8.5a

The answer is 8.5a+38

I'm so sorry if i'm wrong!

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3 years ago

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PIT_PIT [208]

Answer:

5:3, 20:12, 10/3 : 2, and 8 1/3 : 5.

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Step-by-step explanation:

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2 years ago

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lukranit [14]

Answer:

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2 years ago