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SashulF [63]
3 years ago
5

HELP ME PLEASE!❤️ mathematics

Mathematics
1 answer:
kondaur [170]3 years ago
5 0
[19] x2 [38]x2[76]x2[152]x2[304] this is the answer

If u want to know how I get it than divide the number in the box by 2 than u will get the first two missing number than last u divide 152 by 2 to get the last missing number
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Help please <br><br> something+(-4)=-1
omeli [17]
The answer should be 3.
6 0
3 years ago
Performance task A parade route must start And and at the intersections shown on the map. The city requires that the total dista
Flauer [41]

Answer:

  A: the proposed route is 3.09 miles, so exceeds the city's limit

Step-by-step explanation:

The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...

  a^2 = (12-6)^2 +3^2 = 45

  a = √45 = 3√5

and

  b^2 = (6 -2)^2 +4^2 = 32

  b = √32 = 4√2

Then the total length, in grid squares, is ...

  3√5 + 4√2 = 6.7082 +5.6569 = 12.3651

If each grid square is 1/4 mile, then 12.3651 grid squares is about ...

  (12.3651 squares) · (1/4 mile/square) = 3.0913 miles

The proposed route is too long by 0.09 miles.

5 0
3 years ago
Explain why the function is discontinuous at the given number
Blizzard [7]
For f to be continuous at x=5, we need to have

\displaystyle\lim_{x\to5}f(x)=f(5)

Note that x\to5 means that x\neq5, but that x is *approaching* 5. We're told that for x\neq5, we have

f(x)=\dfrac{x^2-5x}{x^2-25}

We can write

\dfrac{x^2-5x}{x^2-25}=\dfrac{x(x-5)}{(x+5)(x-5)}=\dfrac x{x+5}

and the limit would be

\displaystyle\lim_{x\to5}\frac x{x+5}=\dfrac5{5+5}=\dfrac5{10}=\dfrac12\neq1=f(5)

and so f is discontinuous.
5 0
3 years ago
What is the constant rate of change of (5,80) (4,64) and (6,96)
sveticcg [70]

Answer:

16

Step-by-step explanation:

The existence of the constant rate of change is given the ratio of y to x is the same. Then:

k_{1} = \frac{80}{5}

k_{1} = 16

k_{2} = \frac{64}{4}

k_{2} = 16

k_{3} = \frac{96}{6}

k_{3} = 16

In consequence, the constant rate of change is 16.

8 0
3 years ago
8+9x1x2 to the second power it has the 2 above the 2 but I just can't put it there on this
Gnoma [55]
The correct answer is 44
8 0
3 years ago
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