You use the quadratic formula:
2x {}^{2} - 3x = 5
2x {}^{2} - 3x - 5 = 0
x = \frac{3 + - \sqrt{9 -4(2)( - 5)}}{2 \times 2}
x = \frac{3 + - \sqrt{49} }{4}
x = \frac{3 + 7}{4} \: and \: x = \frac{3 - 7}{4}
x = \frac{5}{2} \: and \: x = - 1
No, because one x-value corresponds to two different y-values
Answer:
∡TQS = 10x -3
Step-by-step explanation:
∡TQS = ∡RQS - ∡RQT
= 22x - 11 - (12x - 8)
= 10x -3
Evaluation of square root 169 = 13, so 10 + 13 = 23
Answer:
6.1
⋅
Step-by-step explanation:
i think smh
