Question

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below.
Demetria got a score of 71.471.4; this version has a mean of 66.666.6 and a standard deviation of 88.

Norma got a score of 258.3258.3; this version has a mean of 238238 and a standard deviation of 2929.

Kaitlyn got a score of 88; this version has a mean of 7.27.2 and a standard deviation of 0.40.4.

If the company has only one position to fill and prefers to fill it with the applicant who performed best on the aptitude test, which of the applicants should be offered the job?

Answer 1

Answer:

The job should be offered to Kaitlyn

Step-by-step explanation:

From the question we are told that

   The data for  Demetria is

      Test score is  71.4

      The mean is  66.6

      The standard deviation is 8

Generally the z-sore for Demetria is mathematically evaluated as

        $z - score = \frac{ 71.4 - 66.6 }{ 8}$

= >     $z - score = 0.6$

   The data for  Norma is

      Test score is  258.3

      The mean is  238

      The standard deviation is  29

Generally the z-sore for Norma  is mathematically evaluated as

        $z - score = \frac{ 258.3 - 238 }{ 29}$

= >     $z - score = 0.7$

   The data for  Kaitlyn is

      Test score is  8

      The mean is 7.2

      The standard deviation is  0.4

Generally the z-sore for Norma  is mathematically evaluated as

        $z - score = \frac{ 8 - 7.2}{ 0.4}$

= >     $z - score = 2$

Now given that the z-score of  Kaitlyn is the highest it means that performed best and should be given the job