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3 years ago

If the rectangular screen of a 40-inch monitor is 35 inches wide, what is the height of the monitor? Round to the nearest tenth.

Mathematics

1 answer:

zloy xaker [14]3 years ago

7 0

Answer:

19.4

Step-by-step explanation:

We can solve this question using Pythagorean theorem

40^2 = h^2 + 35^2

1600= h^2+ 1225

1600-1225= h^2

375= h^2

h= √375

h = 19.4

Hence the height is 19.4

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HELPPPP please thanks!!!

Dominik [7]

the answer is one because 1×anything equals what your multiplied one by

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3 years ago

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Which equation has a maximum at y=5 for 0 is less than or equal to x which is less than or equal to 2pi

alekssr [168]

Answer:

From the looks of it I think the answer is C.

3 0

3 years ago

Someone please help solve this!! I’ll give brainlist

dem82 [27]

Answer:

Inital height is 20

Step-by-step explanation:

h= (-5x-5)(x-4)

h= -5x^2+15x+20

7 0

3 years ago

In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline

VLD [36.1K]

Answer:

The measure of the arc CD = 64°

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Kitty [74]

Answer: (-2, 5) and (2, -3)

Step-by-step explanation:

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

y - intercept = (0, 1) 2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

$y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\$

vertex = (1, -4) 2nd point (y-intercept) = (0, -3)

see attached - the graphs intersect at two points: (-2, 5) and (2, -3)

8 0

3 years ago