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3 years ago

Describe the pattern, write the next term, and write a rule for the nth term of the sequence,

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

7 0

Step-by-step explanation:

Next term is - 51

Use formula Tn=a+(n-1)d

a=the first term of the sequence which is - 15

d=the difference between the terms which is - 9

Substitute

Tn=-15+(n-1)(-9)

Tn=-15+9-9n

Tn=-9n-6

From this you will be able to generate all the terms in the pattern

If they say determine the 50th term just substitute 50 by n

Tn=-9(50)-6

Tn=-450-6

Tn=-456

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What is the sum of the geometric series? Sigma-Summation Underscript n = 1 Overscript 4 EndScripts (negative 2) (negative 3) Sup

belka [17]

Answer:

Step-by-step explanation:

∑⁴ₙ₌₁ -144 (½)ⁿ⁻¹

This is a finite geometric series with n = 4, a₁ = -144, and r = ½.

S = a₁ (1 − rⁿ) / (1 − r)

S = -144 (1 − (½)⁴) / (1 − ½)

S = -270

If you wanted to find the infinite sum (n = ∞):

S = a₁ / (1 − r)

S = -144 / (1 − ½)

S = -288

Read more on Brainly.com - brainly.com/question/14504382#readmore

8 0

3 years ago

Read 2 more answers

How many solutions do the following equations have ? Please helppppp

Svetllana [295]

Answer:

a) no solution

b) no Solution

c) -8

d) -1

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Step-by-step explanation:

7 0

3 years ago

Write the equation of a line parallel to the line: y=-x-4 that goes through the point (-9,8)

Ymorist [56]

Answer:

y=-x-1 or, y-8=-1(x+9)

Step-by-step explanation:

Parallel lines have the same slope. in your current equation you have a slope of -1. We can use this slope and your set of points in the point slope formula.

y-y1=m(x-x1)

(-9, 8)

x1 y1 m=-1

y-8=-1(x+9)

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4 years ago

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pshichka [43]

Answer:

The Amount of money in the account after 20 years $22,416.

Step-by-step explanation:

Given as :

The principal deposited into account = $4000

The rate of interest = 9% compounded annually

The time period for deposit = t = 20 years

Let the amount into account after 20 years = $A

now, According to question

From compound Interest method

Amount = principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = $4000 × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, A = $4000 × $(1+\dfrac{\textrm 9}{100})^{\textrm 20}$

Or, A = $4000 × $(1.09)^{20}$

or, A = $4000 × 5.604

So, The amount in account after t years = A = $22,416

Hence, The Amount of money in the account after 20 years $22,416. Answer

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3 years ago

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MakcuM [25]

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