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3 years ago

15

Doreen lives 3/4 mile from the library. Sheila lives 1/3 AS FAR AWAY FROM THE LIBRARY AS DOREEN.

1 answer:

alexdok [17]3 years ago

3 0

What's the question that needs to be solved and I will help?

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I really need help with this question

Step2247 [10]

Answer:

option (b) -3(3w-3.1)

7 0

3 years ago

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I had 13 dollars. My mom gave me 10 dollars. My dad gave me 30 dollars. My Aunt, My Uncle, and Grandma gave me 100 dollars. I ha

posledela

13+10+30+100+7=160 dollars

5 0

3 years ago

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Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Which best explains whether a triangle with side lengths 5 cm, 13 cm, and 12 cm, is a right triangle?

Llana [10]

The Pythagorean Proposition can help you explain this:
${a}^{2} = {b}^{2} + {c}^{2} \\ {13}^{2} = {5}^{2} + {12}^{2} \\ 169 = 25 + 144$

7 0

3 years ago

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1, 1, 4, 7, 8, 8, 8, 11, 15<br> What is the mode of this list of numbers?<br><br> answer asap!!!!

wlad13 [49]

Answer:

8

Step-by-step explanation:

its eight...........................

7 0

3 years ago

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