Probability that x assumes a value between 109.1 and 130.5:
Using a z-score table find the corresponding value for z=-1.47:
2. Find the z-score for P(x<130.5)
3. Subtract the z-score of upper limit by the z-score of lower limit:
Then, the probability that x assumes a value between 109.1 and 130.5 is:
[tex]P(109.1
Answer:
8
Step-by-step explanation:
If you actually need it comment on the bottom of this answer and I´ll edit this!
Answer: 10/36
When a pair of fair dice are rolled , the total possible cases are (6 × 6) = 36. Out of these 36 cases the following 10 cases are favors(giving the sum > 8) for the happening of the event . These 10 cases are (3, 6), (4, 5), (4, 6),(5, 4), (5, 5), (5, 6) , (6, 3), (6, 4), (6, 5), & (6, 6)