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3 years ago

What is the product of a,b, and c?

Mathematics

1 answer:

Yuri [45]3 years ago

6 0

Answer:

$abc = - \frac{16}{3}$

Step-by-step explanation:

${x}^{ - 2} {y}^{3} \sqrt[3]{ 64{x}^{5} {y}^{3} } = a {x}^{b} {y}^{c} \\ \\ {x}^{ - 2} {y}^{3} \times 4 \times {x}^{ \frac{5}{3} } \times y= a {x}^{b} {y}^{c} \\ \\ 4 {x}^{ \frac{5}{3} - 2 } {y}^{3 + 1} = a {x}^{b} {y}^{c} \\ \\ 4 {x}^{ \frac{5 - 6}{3} } {y}^{4} = a {x}^{b} {y}^{c} \\ \\ 4 {x}^{ \frac{ - 1}{3} } {y}^{4} = a {x}^{b} {y}^{c} \\ \\ equating \: like \: terms \: on \: both \: sides \\ \\ a = 4 \\ \\ b = - \frac{1}{3} \\ \\ c = 4 \\ \\ abc = 4 \times ( - \frac{1}{3} ) \times 4 \\ \\ = 16 \times ( - \frac{1}{3} ) \\ \\ abc = - \frac{16}{3}$

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180° measures more than 90°, so according to the given statement, a plane angle is also an obtuse angle, and that is incorrect. From that, we conclude that the statement is not a good definition.

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The given statement is:

"An obtuse angle is an angle whose measure is greater than 90°."

This is the common, but incorrect, definition for obtuse angles.

We know that an angle that measures 180° is called a plane angle and by definition, a plane angle is not an obtuse angle.

And the angles larger than 180° (and smaller than 360°) are the reflex angles.

Now, 180° measures more than 90°, so according to the given statement, a plane angle is also an obtuse angle, and that is incorrect. From that, we conclude that the statement is not a good definition.

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2 years ago

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3 years ago

Find the center of the circle that you can circumscribe about DABC.

Vlada [557]

The center of the circle that circumscribe about DABC is $(h,k) = (1, 5)$ .

A circle can be modelled after a expression of the form:

$A\cdot x + B\cdot y + C =-x^{2}-y^{2}$ (1)

We can determine all coefficients by knowing three <em>distinct</em> points on plane.

If we know that $(x_{1}, y_{1}) = (2, 8)$ , $(x_{2}, y_{2}) = (0, 8)$ and $(x_{3}, y_{3}) = (2, 2)$ , then the solution of the system of linear equations is:

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$8\cdot B + C = -64$ (3)

$2\cdot A + 2\cdot B + C = -8$ (4)

$A = -2, B = -10, C = 16$

Now we proceed to <em>complete</em> squares and factor each resulting perfect square trinomial in order to determine the coordinates of the center of the circle:

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The center of the circle that circumscribe about DABC is $(h,k) = (1, 5)$ .

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3 years ago