What is (1 2/3) dived by (1/8)

Y=770(1.31)^x<br> find percent decrease or increase

aliina [53]

Answer:

it increase by 31%

Step-by-step explanation:

1.31-1.00=.31 move the decimal place to the left 31%

6 0

3 years ago

What is the correct classification of 23x + 16? A. monomial B. binomial C. trinomial

Leokris [45]

Answer: B. binomial.

Step-by-step explanation:

1. You can classify polynomials based on the number of terms the polynomial has:

- If it has one term is classified as a monomial.

- If it has two term is classified as a binomial.

- If it has three terms is classified as a trinomial.

2. The polynomial $23x+16$ has two terms. Therefore, the correct clasification is: binomial.

3. Then, the correct answer is the option B.

5 0

3 years ago

Read 2 more answers

Help please<br> I need to now asap

inessss [21]

Answer:

x = 55.866 ft.

Step-by-step explanation:

39^2 + 40^2 = x^2

1521 + 1600 = 3121

sqrt(3121) = 55.8659

Rounded = 55.866

Make sure to add the ft.

4 0

1 year ago

Read 2 more answers

Suppose a basketball player is practicing shooting, and has a prob-ability .95 of making each of his shots. Also assume that his

Karo-lina-s [1.5K]

Answer:

0.082

Step-by-step explanation:

Number of attempts = n = 100

Since there are only two outcomes and in-dependent of each other, the probability of missing a shot = 1 - Probability of making each shot

p = 1 - 0.95 = 0.05

Possion Ratio (λ) = np where n is the number of events and p is the probability of the shot missing

λ = 100 x 0.05 = 5

Define X such that X = Number of misses and X ≅ Poisson (λ = 5)

P [X ≤ 2] = P [X = 0] + P [X = 1] + P [X = 2]

P [X ≤ 2] = e⁻⁵ + e⁻⁵ x 5 + e⁻⁵ x 5²/2!

P [X ≤ 2] = e⁻⁵ [1 + 5 + 5²/2!]

P [X ≤ 2] = e⁻⁵ x 12.25 = 0.082

The required probability that there are at most 2 misses in the first 100 attempts is 0.082

7 0

3 years ago

Assume that a sample is used to estimate a population proportion p. Find the 95% confidence for a sample of size 246 with 52% su

denpristay [2]

Using the z-distribution, the 95% confidence interval for the proportion is given as follows:

(0.4576, 0.5824).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The other parameters for the interval are given as follows:

$n = 246, \pi = 0.52$ .

The lower and upper bound of the interval, respectively, are given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 - 1.96\sqrt{\frac{0.52(0.48)}{246}} = 0.4576$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 + 1.96\sqrt{\frac{0.52(0.48)}{246}} = 0.5824$

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

6 0

1 year ago