What is the area in square inches of this quadrilateral

Mathematics

2 answers:

Lerok [7]3 years ago

7 0

Answer:

160 in²

Step-by-step explanation:

20 * 16 / 2

if we wouldn't devide with 2, we would calculate the rectangle around the quadrilateral

timama [110]3 years ago

7 0

Answer:

G, 160 in^2

Step-by-step explanation:

Let us start with the general equation to find the area of this quadrilateral, which is noticably a rhombus, $A=\frac{d_1d_2}{2}$ , where the two d represent the two diagonals of the rhombus.

Notice that the longer diagonal consists of two 10in. portions. Let's add them up to find the total length:

$10+10=20$ in.

Now let's find the smaller diagonal consisting of two 8 in. portions:

$8+8=16$ in.

Great! Let's plug in to solve for the area:

$A=\frac{20*16}{2} \\A=\frac{320}{2} \\A=160$

Therefore, the area of the quadrilateral is G, 160 in^2.

I hope this helps! Let me know if you have any questions :)

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Hey!!!
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