Answer:
G, 160 in^2
Step-by-step explanation:
Let us start with the general equation to find the area of this quadrilateral, which is noticably a rhombus,
, where the two <em>d</em><em> </em>represent the two diagonals of the rhombus.
Notice that the longer diagonal consists of two 10in. portions. Let's add them up to find the <u>total length</u>:
in.
Now let's find the smaller diagonal consisting of two 8 in. portions:
in.
Great! Let's plug in to solve for the area:
![A=\frac{20*16}{2} \\A=\frac{320}{2} \\A=160](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B20%2A16%7D%7B2%7D%20%5C%5CA%3D%5Cfrac%7B320%7D%7B2%7D%20%5C%5CA%3D160)
<u>Therefore, the area of the quadrilateral is G, 160 in^2.</u>
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<em>I hope this helps! Let me know if you have any questions :)</em>