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Marina CMI [18]
2 years ago
13

What is the area in square inches of this quadrilateral

Mathematics
2 answers:
Lerok [7]2 years ago
7 0

Answer:

160 in²

Step-by-step explanation:

20 * 16 / 2

if we wouldn't devide with 2, we would calculate the rectangle around the quadrilateral

timama [110]2 years ago
7 0

Answer:

G, 160 in^2

Step-by-step explanation:

Let us start with the general equation to find the area of this quadrilateral, which is noticably a rhombus, A=\frac{d_1d_2}{2}, where the two <em>d</em><em> </em>represent the two diagonals of the rhombus.

Notice that the longer diagonal consists of two 10in. portions. Let's add them up to find the <u>total length</u>:

10+10=20in.

Now let's find the smaller diagonal consisting of two 8 in. portions:

8+8=16in.

Great! Let's plug in to solve for the area:

A=\frac{20*16}{2} \\A=\frac{320}{2} \\A=160

<u>Therefore, the area of the quadrilateral is G, 160 in^2.</u>

<u />

<em>I hope this helps! Let me know if you have any questions :)</em>

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