What is the area in square inches of this quadrilateral
2 answers:
Answer:
G, 160 in^2
Step-by-step explanation:
Let us start with the general equation to find the area of this quadrilateral, which is noticably a rhombus, , where the two <em>d</em><em> </em>represent the two diagonals of the rhombus.
Notice that the longer diagonal consists of two 10in. portions. Let's add them up to find the <u>total length</u>:
in.
Now let's find the smaller diagonal consisting of two 8 in. portions:
in.
Great! Let's plug in to solve for the area:
<u>Therefore, the area of the quadrilateral is G, 160 in^2.</u>
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<em>I hope this helps! Let me know if you have any questions :)</em>
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Hello!
Recall that the transformations form of a parabola is:
f(x) = ±a(b(x-h)) + k where:
a = vertical stretch/compression
b = horizontal stretch/compression
h = horizontal shift, x-coordinate of vertex
k = vertical shift, y-coordinate of vertex
In this instance, the parent function is f(x) = 3x^2. There is a vertical stretch of 3.
However, there is a point (7, -2) that needs to be included. Substitute these values into the transformation formula:
h = 7
k = -2
f(x) = 3(x - 7)² - 2 is the equation with (7, -2) as the vertex.