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MakcuM [25]
3 years ago
15

What are the measures of angle B and D

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

Step-by-step explanation:⇔

∠B

∠D

are the measures but if you forgot to add the picture then... who knows

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Describe how the product of 0.4 × 2 would look on a ten-square grid. The product would have _____ squares shaded out of 10.
krek1111 [17]
0.8 squares shaded out of 10

You just do 4x2 which is 8

Then add the 0. In front of 8

Easy as that
8 0
3 years ago
HELPPP!! ASAP NO ROCKY LIL HOMIE I NEED TO PASS THIS YEAH
enyata [817]

Answer:

take away the 15 because you can't multiply a diagonal so 12x18=216 reduce it by the 15 would be the first one sir

Step-by-step explanation:

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3 years ago
Justin has $450 to buy supplies for the school computer lab. He buys 8 boxes of printer paper that cost $49 each. About how much
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He spend 392 dollars on copy paper
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3 years ago
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Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
Given that y varies directly with x in the table below, what is the value of y if the value of x is 7?
Paha777 [63]

Answer:

y = 42

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use an ordered pair from the table.

Using x = 2 when y = 12, then

12 = 2k ( divide both sides by 2 )

6 = k

y = 6x ← equation of variation

When x = 7, then

y = 6 × 7 = 42

4 0
3 years ago
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