Answer:
Step-by-step explanation:
If we take out the extra $3, we can group the bills into one each of $5 and $1, for a value of $6. There will be 7 such groups in the remaining $42.
That means there are 7 bills of the $5 denomination, and 3 more than that (10 bills) of the $1 denomination.
There are 7 $5 bills and 10 $1 bills.
_____
If you want to write an equation, it is usually best to let a variable stand for the most-valuable contributor. Here, we can let x represent then number of $5 bills. Then the value of the cash box is ...
5x +(x+3) = 45
6x = 42 . . . . . . . . subtract 3, collect terms
x = 7 . . . . . . . . . . . there are 7 $5 bills
x+3 = 10 . . . . . . . . there are 10 $1 bills
You may notice that this working parallels the verbal description above. (After we subtract $3, x is the number of $6 groups.)
I hope this helps you
Brandon x
Michael 3x
18 years ago
Brandon x-18
Michael 3x-18
9 (x-18)=3x-18
9x-9.18=3x-18
9x-3x=9.18-18
6x=8.18
x=8.3
x= 24
D 24 do order of operations perenthesis, exponents, multiplication or division, addition or subtraction
Can you make this more clear?? not really sure what I'm supposed to be doing here
