Answer: Probability of scoring 2 hits = 0.63.
Step-by-step explanation:
Since we have given that
Number of dart throws at a target = 3
Probability of scoring a hit on any one throw = 30%
We will use "Binomial Distribution" i.e.

where,
n denotes number of dart throws at a target,
r denotes number of required throws
p denotes probability of success
(1-p) denotes probability of failure
So, Probability of success is given by

Probability of failure is given by

We will use "Binomial Distribution" i.e.

Hence, Probability of scoring 2 hits = 0.63.