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Nina [5.8K]
3 years ago
11

What happened after the British became more imperialistic and forced China to sign trade agreements? Imports to China and export

s from China grew. Great Britain and China merged industries. Imports to Britain grew, but exports to China fell. China refused to honor the agreements.
Mathematics
2 answers:
Sergio039 [100]3 years ago
7 0

Answer:

Imports to China and exports from China grew.

Step-by-step explanation:

Got 100 percent on Edge. Don't trust the first answer.

vesna_86 [32]3 years ago
4 0

Answer:

a edg 2020

Step-by-step explanation:

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8.5 is 50% of what number
zaharov [31]
The answer is going to be 17%. hope that helped
8 0
2 years ago
4,000000 has more whole number places than 40,000
jonny [76]
You have divided 4,000000 by 100 so it became 40000 so 4000000 has 100 more whole number places 
3 0
3 years ago
A triangular flag has an area of 22 cm². Jon measures the height as 8 cm, what is the base length?
dedylja [7]
The base length is 5.5 cm.

Explanation:

Area of triangle = base x height x 1/2

Let b cm be the base length of the triangular flag.

22 = b x 8 x 1/2

22 x 2 ÷ 8 = b

b = 44 ÷ 8

b = 5.5
4 0
2 years ago
A computer maker receives parts from three suppliers, S1, S2, and S3. Fifty percent come from S1, twenty percent from S2, and th
rewona [7]

Answer:

a) 4.9 % of all parts is defective or 0.049 of the total parts.

b)  0.5102 is the probability that the defective part was supplied by S1

Step-by-step explanation:

N is the total number of parts from supplier S1, S2 and S3.

N1 = 0.5*N is the total number of part supplied by S1

N2 = 0.2*N is the total number of part supplied by S2  

N3 = 0.3*N is the total number of part supplied by S3

a) if Nd1 is the number of defective parts from supplier S1, Nd2 is the number of defective parts from supplier S2 and Nd3 is the number of defective parts from supplier S3, the the total defective parts Nd is:

Nd = Nd1 + Nd2 + Nd3, where

Nd1 = 0.05*N1 = 0.05*0.5*N = 0.025*N,

Nd2 = 0.03*N2 = 0.03*0.2*N = 0.006*N,

Nd3 = 0.06*N3 = 0.06*0.3*N = 0.018*N,

Then Nd = Nd1 + Nd2 + Nd3 =  0.049*N, so Nd/N = 0.049

b) P(S1 \vert d) = \frac{P(S1,d)}{P(d)} = \frac{P(d \vert S1)}{P(d)} = \frac{0.05*0.5}{0.049} \approx 0.5102

for the last expression I used the Bayes tehorem.

P(S1 \vert d) is the probability that occur S1 given that d (defective) is true. This a conditional probability.

see at https://en.wikipedia.org/wiki/Bayes%27_theorem

6 0
2 years ago
There are two numbers. The first number minus the second number is 15. One-third of the sum of the numbers is one quarter of the
disa [49]

Answer:

So the numbers are 12 and -3.

Step-by-step explanation:

In order to solve this problem we will attribute variables to the numbers, the first one will be "x" and the second one will be "y". From the first sentence we know that the subtraction of the two numbers is equal to 15, so we have:

x - y = 15

Then the problem states that one-third of the sum of the number is equal to one quarter of the first number, so we have:

(1/3)*(x+y) = x/4

Since we now have two equations and two variables we can solve for x and y. From the first equation we have:

y = x - 15

Using this expression for the value of y in the second equation:

(1/3)*(x + x - 15) = x/4

(1/3)*(2*x - 15) = x/4

2*x - 15 = 3*x/4

2*x - 3*x/4 = 15

(8*x - 3*x)/4 = 15

5*x/4 = 15

5*x = 60

x = 60/5 = 12

y = x - 15 = 12 - 15 = -3

So the numbers are 12 and -3.

4 0
2 years ago
Read 2 more answers
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