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Vilka [71]
2 years ago
8

How long would it take for the value of the account to reach $880 to the nearest tenth of a year?

Mathematics
1 answer:
Pavel [41]2 years ago
6 0

Answer:

I think the answer is 7.5

Step-by-step explanation:

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A fraction with a numerator that is greater than or equal to the denominator is an
GarryVolchara [31]
****Equal to one or greater than 1***
3 0
3 years ago
9. Carla has $200 in her bank account.
Firdavs [7]

(a) Linear Equation:   f(x) = 200 - 20x

(b) x-intercept : (10,0)

(c) y-intercept : (0,200)

(d) Domain : {0,1,2,3,4,5,6,7,8,9,10}

    Range : {0,1,2,...,200}

Step-by-step explanation:

Step 1: As we can see in graph, money in Carla is decreasing in multiples of 20 can be referred as 20x.

Every week $20 is getting deducted from the total amount of $200.

Step 2: (a) So we can quote it in equation as,

f(x) = 200 - 20x

where x represents number of weeks

Step 3: (b) x-intercept is where value of y becomes 0.

So, referring graph we can determine x intercept as x = 10. Point (10,0). which also means no money left in account.

Step 4: (c) y-intercept is where value of x becomes 0.

So, referring graph we can determine y intercept as y = 200. Point (0,200). which is starting value of money in account.

Step 5: (d) Domain : {0,1,2,3,4,5,6,7,8,9,10}

                  Range : {0,1,2,...,200}

4 0
3 years ago
Solve for X. (1 point)<br> -ax + 3b &gt; 5
Anarel [89]

Answer:

x<(3b-5)/a

Step-by-step explanation:

Subtract 3b from both sides: -ax>5-3b

Divide by -a, when dividing/multiplying a negative you flip the </> sign: x<(3b-5)/a

4 0
3 years ago
−76 = −0.8k <br><br> k =<br><br> What number represents k
Over [174]

Answer:

k= 95

Step-by-step explanation:

-76=-0.8k

-76/-0.8=k

95=k

k= 95

8 0
2 years ago
HELP
vodka [1.7K]
So I = Prt 

I for interest charge 
P for principal ($4,840)  
r for rate (6%)
t for time (2 yrs) 

So you would then plug the information into the equation.....

I = 4,840*.06*2 
I = 580.80 

So the answer to your question is $580.80 which is option B

Hope this helps! :) 
6 0
3 years ago
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