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Tresset [83]
3 years ago
11

Babe Ruth steps to the plate and casually points to left centerfield to indicate the location of his next home run. Themighty Ba

be holds his bat across his shoulder, with one handholding the small end of the bat. The bat is horizontal, andthe distance from the small end of the bat to the shoulder is22.5cm. If the bat has a mass of 1.1kg and has a center ofmass that is 67vm from the small end of the bat, find the magnitudeand direction of the force exerted by:________
a) the hand
b) the shoulder.
Physics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

Fs = 32N

Fh = 21 N

Explanation:

Statics

Let Fs be the force of the shoulder, assumed upward

Let Fh be the force of the hand, assumed downward

Sum moments about the hand to zero

1.1(9.8)[67] - Fs[22.5] = 0

Fs = 32N

Sum vertical forces to zero

32 - Fh - 1.1(9.8) = 0

Fh = 21 N

Or we could sum moments about the shoulder point

1.1(9.8)[67 - 22.5] - Fh[22.5] = 0

Fh = 21 N

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Answer:

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Explanation:

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150+10c+150-10c=1.5(15-c)(15+c)

300=1.5(225-c^2)

300=337.5-1.5c^2

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How does the sun's gravity and the earth inertia keep us orbiting in the solar system
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8 0
3 years ago
Read 2 more answers
An object is placed in front of a diverging lens, such that the object-to-image distance is 71 cm.
Pachacha [2.7K]

Explanation:

Given that,

Object-to-image distance d= 71 cm

Image distance = 26 cm

We need to calculate the object distance

u -v= d

u=71+26=97\ cm

We need to calculate the focal length

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-26}+\dfrac{1}{97}

\dfrac{1}{f}=-\dfrac{71}{2522}

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(B). Given that,

Object distance = 95 cm

Focal length = 29 cm

We need to calculate the distance of the image

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value in to the formula

\dfrac{1}{-29}=\dfrac{1}{v}-\dfrac{1}{95}

\dfrac{1}{v}=\dfrac{1}{-29}-\dfrac{1}{95}

\dfrac{1}{v}=-\dfrac{124}{2755}

v=-22.21\ cm

We need to calculate the magnification

Using formula of magnification

m=\dfrac{v}{u}

m=\dfrac{22.21}{95}

m=0.233

The magnification is 0.233.

The image is virtual.

Hence, This is the required solution.

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3 years ago
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