Question

A) How long (in ns) does it take light to travel 1.0 m in a vacuum?

Answer 1

Answer:

a

      $t = 3.33 \ ns$

b

i      $D_w =0.75 \ m$

ii     $D_g =0.67 \ m$

iii     $D_c =0.46 \ m$

Explanation:

Generally the time taken to travel 1 m in a vacuum is mathematically represented as

       $t = \frac{1}{c}$

Here c is the speed of light with value  $c = 3.0*10^{8} \ m/s$

So  

          $t = \frac{1}{3.0*10^{8}}$

          $t = 3.33*10^{-9} \ s$

         $t = 3.33 \ ns$

The distance light travels in water is mathematically represented as

         $D_w = \frac{c}{n_w} * t$

Here n_w  is the refractive index of  water with value 1.333

So

      $D_w = \frac{3.0*10^{8}}{1.333} * 3.33*10^{-9}$

     $D_w =0.75 \ m$

The distance light travels in glass is mathematically represented as

       $D_g = \frac{c}{n_g} * t$

Here n_g  is the refractive index of  glass with value 1.5

So

      $D_g = \frac{3.0*10^{8}}{1.5} * 3.33*10^{-9}$

     $D_g =0.67 \ m$

The distance light travels in cubic zirconia is mathematically represented as

       $D_c = \frac{c}{n_g} * t$

Here n_c  is the refractive index of cubic zirconia with value 2.15

So

      $D_c = \frac{3.0*10^{8}}{2.15} * 3.33*10^{-9}$

     $D_c =0.46 \ m$