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matrenka [14]
3 years ago
12

Convert one mean solar day into second​

Physics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

86400 seconds

Explanation:

To convert a mean solar day to second :

Number of hours in a solar day = 24 hours

Number of minutes per hour = 60 minutes

Number of seconds per minute = 60 minutes

Hence, the number of seconds in a solar day is :

(Number of hours in a solar day * number of minutes in an hour * number of seconds in a minute)

(24 * 60 * 60) seconds = 86400 seconds

Hence, 1 mean solar day = 86400 seconds

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What are the differences between forces and pressure​
slamgirl [31]

Answer:

Force is a push or pull action between objects. Pressure is force acting on a surface area of an object, thus it is force per unit area.

Explanation:

4 0
3 years ago
A cart moves with negligible friction or air resistance along a roller coaster track. The cart starts from rest at the top of a
lina2011 [118]

Answer:

hinit = 17.5 m

Explanation:

  • Assuming no friction present, the mechanical energy must be conserved, which means that at any point of the trajectory, the sum of the gravitational potential energy and the kinetic energy must keep the same.
  • At the top of the hill, since it starts from rest, all the energy must be potential, and we can express it as follows:

       E_{o} = U_{o} = m*g*h_{init}  (1)

  • When the car arrives to the top of the second hill, as we know that it is lower than the first one, the energy of the car, must be part gravitational potential energy, and part kinetic energy.
  • We can express this final energy as follows:

       E_{f} = U_{f} + K_{f}  = m*g* h_{2} + \frac{1}{2} *m*v_{f} ^{2}  (2)

  • In order to find hinit, we need to make (1) equal to (2), and solve for it.
  • In (2) we have the value of h₂ (10 m), but we still need the value of the speed at the top of the second hill, vf.
  • Now, when the car is at the top of the hill, there are two forces acting on it, in opposite directions: the normal force (upward) and the weight (downward).
  • We know also that there is a force that keeps the car along the circular track, which is the centripetal force.
  • This force is just the net downward force acting on the car (it's vertical at the top), and is just the difference between the weight and the normal force.
  • If the cart just barely loses contact with the track at the top of the second hill, this means that at that point the normal force becomes zero.
  • So, the centripetal force must be equal to the weight.
  • The centripetal force can be expressed as follows:

       F_{c} = m*\frac{v_{f} ^{2}}{R}  (3)

  • We have just said that (3) must be equal to the weight:

       F_{c} = m*\frac{v_{f} ^{2}}{R} = m*g (4)

  • Simplifying, and rearranging, we can solve for vf², as follows:

       v_{f}^{2} = R*g  (5)  

  • Replacing (5) in (2), simplifying and rearranging in (1) and (2) we finally have:

      h_{init} = h_{2} + \frac{1}{2} R = 10m + 7.5 m = 17.5 m (6)

7 0
3 years ago
What is the peak emf generated (in V) by rotating a 1000 turn, 42.0 cm diameter coil in the Earth's 5.00 ✕ 10−5 T magnetic field
ELEN [110]

Answer:

5.77 Volt

Explanation:

N = 1000, Diameter = 42 cm = 0.42 m,  t = 12 ms = 12 x 10^-3 s

Change in magnetic field, B = 5 x 10^-5 T

The peak value of emf is given by

e = N x dФ / dt

e = N x A x dB/dt

e = (1000 x 3.14 x 0.21 x 0.21 x 5 x 10^-5) / (1.2 x 10^-3)

e = 5.77 Volt

3 0
3 years ago
A compound microscope has an objective lens of focal length 1.40 cm and an eyepiece with a focal length of 2.20 cm. The objectiv
olchik [2.2K]

Answer:

magnification is - 159

objective distance is 3.85 cm

Explanation:

Given data

focal length f1 = 1.40 cm

focal length f2 = 2.20 cm

separated d = 19.6 cm

to find out

angular magnification and How far from the objective

solution

we know magnification formula that is

magnification = ( - L / f1 ) (D/f2)

here D = 25 cm put all value

magnification = ( - 19.6 / 1.40 ) (25/2.20)

magnification = - 159

and

now we apply lens formula

i/f = 1/q + 1/p

p = f2 = 2.20

so

q = f2 p / p -f2

q = 1.4(2.20) / ( 2.2 - 1.4 )

q = 3.85 cm

so objective distance is 3.85 cm

3 0
3 years ago
The mass of the sun is 2*10^30 kg and its radius is
Marta_Voda [28]

Explanation:

Distance d=1.5×108 km=1.5×1011 m

Mass of the sun, m=2×1030 kg

Mass of the earth, M=6×1024 kg

Force of gravitation, F=G×d2m×M

F=6.7×10−11×(1.5×1011)22×1030×6×1024=3.57×1022 N

4 0
3 years ago
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