Answer:
A=556
Step-by-step explanation:
Hope this Helps :)
Step-by-step explanation:
Both of them had $x
Later
Jensen=x-64
Raju=x-148
Jensen=3*Raju
x-64=3(x-148)
x-64=3x-444
3x-x=444-64
2x=380
x=$190
Answer: 3× (w +5)
Step-by-step explanation:
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

Using the quadratic formula, the solution for our problem is

The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have

The root is

Then, the maximum height is

1029.99 meters above sea level.
Answer:

Where
represent the total pressure and
the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

And replacing we got:

Step-by-step explanation:
For this case the partial presure of carbon dioxide is given by:

Where
represent the total pressure and
the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

And replacing we got:
