Answer:
Step-by-step explanation:
We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with , , , and respectively since each one is 1 point more than the last.
Add all of these values up and set it all equal to .
Now, simplify.
Subtract on both sides.
Divide both sides by .
Since Louise's score is , the answer is .
<h3>Double-checking</h3>
To verify our answer, add the point totals , , , and .
This equals , so we can be sure the answer is correct.
Answer:
1/4
Step-by-step explanation:
The chance of it landing heads up once would be 1/2
The chance of it landing heads up twice would be 1/4
The chance of it landing heads up three times would be 1/8
The chance of it landing heads up four times would be 1/16
See the pattern?
Pattern: <em><u>Divide the denominator by 2.</u></em>
<h2>
<em>Please give brainliest!!! :) </em></h2>
Answer:
3 boxes
Step-by-step explanation:
because 3 times 9 is 27.
Answer:
Approximately (.) (Assume that the choices of the passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all floors.)
Step-by-step explanation:
If there is no requirement that no two passengers exit at the same floor, each of these passenger could choose from any one of the floors. There would be a total of unique ways for these passengers to exit the elevator.
Assume that no two passengers are allowed to exit at the same floor.
The first passenger could choose from any of the floors.
However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only floors.
Likewise, the third passenger would have to choose from only floors.
Thus, under the requirement that no two passenger could exit at the same floor, there would be only unique ways for these two passengers to exit the elevator.
By the assumption that the choices of the passengers are independent and uniform across the floors. Each of these combinations would be equally likely.
Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:
.