Question

What is an equation of the line that passes through the point (5,-3) and is parallel to the line x+5y=45?

Answer 1

$\btext{x+5y=-10}$

Step-by-step explanation:

When two lines are parallel,their slopes are equal.

Given line is $x+5y=45$.

Let $m$ be the slope of the line.

$m=-5$.

It is given that the line passes through the point $(5,-3)$.

The equation of the line passing through $(x_{1},y_{1})$ and has slope $m$ is $y-y_{1}=m(x-x_{1})$

$x_{1}=5$

$y_{1}=-3$

$m=-5$

So, the equation is $y-5=-5(x+3)$

which simplifies to $x+5y=-10$