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Vesna [10]
3 years ago
10

Arnold is planning on painting a mural. Before painting the mural, Arnold painted the picture on a paper that is 5 inches wide a

nd 11 inches tall. Arnold is using a scale in which 12 inch represents 1 foot to paint the mural.
How wide and tall will the actual mural be?
Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0
0.42ft
0.92 ft
Hope it helps
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write the standard form of the equation of the circle with endpoints of a diameter at the points (9,2) and (-7,5)
AnnyKZ [126]

Answer:

Step-by-step explanation:

Answer:

(x-1)²+(y-3.5)² = 265/4

Step-by-step explanation:

first find the midpoint (center of the circle)

(9+-7)/2, (2+5)/2

(1, 3.5) = center

then distance formula to find diameter

√(9- -7)²+(2-5)²=√256+9 = √265

The radius is half the diameter = (√265)/2

Formula for circle is (x-h)²+(y-k)²=r², where (h, k) is the center

Now you can plug everything in.

(x-1)²+(y-3.5)² = 265/4

4 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
The base of a pentagonal prism is regular with an apothem of 4 cm. The height of the prism is 16 cm. Find the volume of the pris
Georgia [21]

Answer:

volume ≈ 930 cm³ (nearest cubic cm)

Step-by-step explanation:

The base of the prism which is a pentagon is regular. The apothem which is a line drawn from the center to any side of the pentagon is 4 cm. The height of the prism is 16 cm.

The volume of a prism = Bh

where

B = base area

h = height of the prism

The base of the prism can be divided into 5 congruent triangles.But the base of the triangles is unknown.

The sum of interior angle of a pentagon is 540°. That means each angle is 108° . The triangle divide the angle into 2. Making the 2 base angle as 54° each. The last angle of the triangle at the center is 72°(remember sum of angle in a triangle is 180° which is 54° + 54° + 72° = 180°) .

The angle form the center can be divided by the line of height of the triangles. The angle will then be 36°. Using tangential ratio half of the length of the base of the triangle can be known. Therefore,

tan 36° = opposite/adjacent

tan 36° = opposite/4

opposite = 4 tan 36°

The full base of the triangles = 2(4 tan 36°)

area of each triangle = 1/2 × 2(4 tan 36°) × 4 = 16 tan 36°

Base area of the prism(pentagon) = 5 × 16 tan 36° = 80 tan 36°

Volume of the prism = Bh

where

h = 16 cm

B = 80 tan 36°

volume =  80 tan 36° × 16 = 1280  tan 36° = 1280  × 0.726542528

volume = 929.974435847  cm³

volume ≈ 930 cm³ (nearest cubic cm)

5 0
3 years ago
8X + 1 = 49. what is X?​
Zolol [24]

Answer:

5 0
3 years ago
Read 2 more answers
Match the base to the corresponding height.
allochka39001 [22]

Answer:

I can't see the picture

Step-by-step explanation:

SORRY :(

7 0
3 years ago
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