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2 years ago

Use properties of operations to complete the equivalent expression. 5(y+9)=_y+_ 5(y+9)=nothingy+nothing

Mathematics

1 answer:

laiz [17]2 years ago

5 0

Answer:

5y+45

Step-by-step explanation:

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Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention

Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

$a=\frac{d^2s}{dt^2}$

Differentiate the position vector with respect to t.

$\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}$

Differentiate both sides of the obtained equation with respect to t.

$\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}$

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

$\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}$

The initial position is obtained at t=0. Substitute t=0 in the given position function.

$\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}$

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A radio station sells buttons and bumper stickers at a local fair. The buttons cost $2.95 each, and the bumper stickers cost $3.

MA_775_DIABLO [31]

you question isn't quite clear.....

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2 years ago

If u play or know about baseball help me with this

Alenkasestr [34]

Answer:

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3 years ago

aj paid $31.86 for a new basketball. The price he paid included sales tax of 6.25%. Which equation can be used to find the price

asambeis [7]

It A)<span>p + 0.0625p = 31.86</span>

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3 years ago

-5b + 8 < 3<br> What’s the correct answer

sp2606 [1]

Answer:

b>1

Step-by-step explanation:

-5b+8<3

-5b<3-8

-5b<-5

5b<5

b<5/5

b<1

b>1

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2 years ago

Use properties of operations to complete the equivalent expression. 5(y+9)=​___y+​___ 5(y+9)=nothingy+nothing

Use properties of operations to complete the equivalent expression. 5(y+9)=_y+_ 5(y+9)=nothingy+nothing