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Zolol [24]
3 years ago
13

Use properties of operations to complete the equivalent expression. 5(y+9)=​___y+​___ 5(y+9)=nothingy+nothing

Mathematics
1 answer:
laiz [17]3 years ago
5 0

Answer:

5y+45

Step-by-step explanation:

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67.901 + 4.2
joja [24]
I dont understand this what do the numbers represent
3 0
3 years ago
Read 2 more answers
What is the y-intercept, b, of the additive relationship represented by this table?
algol13

Answer:

3

Step-by-step explanation:

First step: Find the slope, Using the Formula y2 - y1 / x2 - x1 =  

6-4=2  3-1=2 then u divde the y/x   2/2=1 So the slope is 1.

Step 2: Use the Slope- Intercept formula, Y=mx+b so 4 = 1(1)+b so 4 = 1 + b

Step 3: subtract 1 on both sides so 4-1=3 1-1=0  so 3 is the Y-Intercept.

3 0
3 years ago
A research group wants to know if the online platform to play Settlers of Catan is being accessed more after the stay at home or
Gre4nikov [31]

Answer:

a) The P-value is 0.

At a significance level of 0.05, there is enough evidence to support the claim that the online platform was accessed significantly more so than before the stay at home order.

b) Effect size d = 0.77

Medium.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the online platform was accessed significantly more so than before the stay at home order.

Then, the null and alternative hypothesis are:

H_0: \mu=1000\\\\H_a:\mu> 1000

The significance level is 0.05.

The sample has a size n=108000.

The sample mean is M=1378.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=489.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{489}{\sqrt{108000}}=1.488

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1378-1000}{1.488}=\dfrac{378}{1.488}=254.036

The degrees of freedom for this sample size are:

df=n-1=108000-1=107999

This test is a right-tailed test, with 107999 degrees of freedom and t=254.036, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>254.036)=0

As the P-value (0) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that the online platform was accessed significantly more so than before the stay at home order.

The effect size can be estimated with the Cohen's d.

This can be calculated as:

d=\dfrac{M-\mu}{\sigma}=\dfrac{1378-1000}{489}=\dfrac{378}{489}=0.77

The values of Cohen's d between 0.2 and 0.8 are considered "Medium", so in this case, the effect size d=0.77 is medium.

5 0
3 years ago
PLS HELP ASAP ILL GIVE BRAINLKEST PLS THANKS
Lerok [7]
I think it would -2!! Sorry if I’m wrong
4 0
2 years ago
Graphing required <br><br><br><br> answer ASAP
raketka [301]
This the answer l guess

5 0
3 years ago
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