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NISA [10]
3 years ago
12

On April 1, year 1, Mary borrowed $130,000 to re-finance the original mortgage on her principal residence. Mary paid 1 points to

reduce her interest rate from 7% to 6%. The loan is for a 30-year period. How much can Mary deduct in year 1 for her points paid?
Business
1 answer:
Simora [160]3 years ago
4 0

Answer:

Mary can deduct $1,300 in year 1 for her points paid.

Explanation:

a) Data and Calculations:

April 1, Amount borrowed by Mary to refinance the original mortgage on her principal residence = $130,000

Payment of 1 points to reduce Mary's interest rate from 7% to 6% amounts to 1% of $130,000 = $1,300.

b) Mary paying 1 points is beneficial to her since her interest cost is reduced from 7% to 6%.  This implies that her total finance cost at the end of the 30-year period will be reduced.

You might be interested in
Kathleen Cole Inc. acquired the following assets in January of 2012. Equipment, estimated service life, 5 years; salvage value,
Lunna [17]

Answer:

1. Debit : Equipment Depreciation : $102000

Credit : Equipment Accumulated Depreciation : $102000

2. Debit : Building Depreciation account : $16857

Credit : Building Accumulated Depreciation : $16857

Explanation:

A change in accounting estimate occurs when there is new information that surfaces, affecting the initial situation. It can affect the carrying amount of an asset or liability as well as alter the accounting for existing and future assets or liabilities.

1. The equipment has a cost of $525000 and its depreciation was changed to using the straight line method after 3 years of use. Straight- line depreciation per year:

(Cost of asset - salvage value) / number of useful years.

The cost of asset and the number of useful years left would have to be found since the machine already depreciated using the sum-of-years-digits.

Number of useful years left : 5 - 3 = 2

Accumulated depreciation is required to find what the asset costs at the beginning of 2015.

Depreciation using sum-of-years-digits:

Sum-of-years-digits is an accelerated form of depreciation based on the assumption that an asset’s productivity reduces with time.

(Cost - Salvage value) x (remaining useful life of asset / sum of years digits)

Sum-of-years-digits = 1 + 2 + 3 + 4 + 5 = 15

Depreciation for 2012 :

($525000 - $15000) / (5/15) = $170000

Depreciation for 2013 :

($525000 - $15000) / (4/15) = $136000

Depreciation for 2014 :

($525000 - $15000) / (3/15) = $102000

Total depreciation: $102000 + $136000 + $170000 = $408000

Cost of asset at Jan 2015 = $525000 - $408000 = $117000

Thus, depreciation expense for 2015 = ($117000 - $15000) / 2 = $51000

Debit : Equipment Depreciation : $51000

Credit : Equipment Accumulated Depreciation : $51000

2. The building has a cost of $693000. It is depreciated using the straight-line method of depreciation. Hence, the depreciation expense is the same annually throughout the life of the asset.

Annual depreciation = (Cost of asset - salvage value) / number of useful years

Useful number of years was initially 30 years, later in 2015, it was changed to 40 years.

In order to find the depreciation for 2015, we need to find the cost of asset at the beginning of 2015 and the estimated useful life years left.

Estimated useful life years left : 40 - 3 = 37 years

Cost of asset :

To find this, we require the accumulated depreciation.

Depreciation for one year:

(693000 - 0) / 30 = $23100

$23100 x 3 = $69300 for 3 years

Cost of asset at the beginning of 2015 :

693000 - $69300 = $623700

This would mean that the depreciation expense for 2015 is:

($623700) / 37 = $16857

Debit : Building Depreciation account : $16857

Credit : Building Accumulated Depreciation : $16857

3 0
3 years ago
Today you purchase a $600 face-value, 8% coupon bond for $600. This bond matures over 10 years. What is the value of the cash fl
Nadya [2.5K]

Answer:

the value of the cash flow in year 5 is -$48

Explanation:

Cash flow in year 5 include a capital repayment and interest expense.This can be determined by constructing an amortization schedule from the data given.

The first step in constructing the amortization schedule is to find the Yield to Maturity.

Pv = -$600

Pmt = $600 × 8% = $48

P/yr = 1

N = 10

Fv = $600

YTM = ?

Using a Financial Calculator the Yield to Maturity is 8%.

then to determine the cash flow for year 5, we need the coupon amount (interest) and the amount of capital repayment.

Coupon  $48

Capital     $0

Total       $48

Therefore the cash flow in year 5 is -$48.

8 0
3 years ago
Thompson Company incurred research and development costs of $100,000 and legal fees of $30,000 to acquire a patent. The patent h
wariber [46]

Answer:

b. 3,000

Explanation:

The computation of the  Patent Amortization Expense in the first year is shown below:

= Legal fees to acquire a patent ÷ estimated useful life

= $30,000 ÷ 10 years

= $3,000

Only the legal expense would be amortized in a year.

And, the lesser period of legal life i.e 20 years and useful life i.e 10 years would be taken in the computation part. So, the lesser time period would be considered i.e useful life of 10 years

7 0
3 years ago
Read 2 more answers
5. An ATM allows a customer to withdraw a maximum of $400. If the customer withdraws more than $200, the service charge is 3% of
tankabanditka [31]

Answer:

//algorithm for ATM money withdrawal

Algorithm: Algorithm for cash withdrawals from ATM.

Input: withdraw_amount

Output: amount+service_charges.

Algorithm:

step 1:

  balance =account balance.

  withdraw_amount = (Get input from user)

 

step 2:

  if(withdraw_amount>400)

      then, print "maximum limit exceeds"

 

step 3:

  if(withdraw_amout<1)

      then, print "enter a valid amount"

 

 

step 4:

  if(withdraw_amount>balance)

      then, print "insufficient balance.. withdraw money $30 as service charges "

 

 

step 5:

  if(withdraw_amount<400 && withdraw_amount<balance)

      if(withdraw_amount>200)

          service_charge=withdraw_amount*(3/100)

          print " Your cash is dispensed... total amount withdrawn +service_charges 30% (withdraw_amount +service_charge) "

4 0
3 years ago
Harper Corp.'s sales last year were $395,000, and its year-end receivables were $42,500. Harper sells on terms that call for cus
Ilya [14]

Answer:

9 average days late

Explanation:

Days Sales Outstanding - Allowed credit period = average days late

Days Sales Outstanding

\frac{Account \: Receivable}{Sales} \times 365 = DSO

\frac{42,500}{395,000} \times 365 = DSO

DSO = 38.81012658 = 39 days

Days Sales Outstanding - Allowed credit period = average days late

39 - 30 = 9 average days late

7 0
3 years ago
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