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3 years ago

12

There are 36 windows in the folsom’ house. the number of window is 3 times as many as the number of closets and 4 more than the

number of doors inside the house. how many closets are in the house? show your work.

1 answer:

xz_007 [3.2K]3 years ago

8 0

Answer:

66

Step-by-step explanation:

36x4=144

36x3=78

144-78=66

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Answer:

Well, 10

Step-by-step explanation:

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I need help with this question

Ghella [55]

${6}^{2} - {5}^{2} \\ 36 - 25 \\ 11$
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3 years ago

F-20f=21 what’s the answer

Virty [35]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{F \ = \ -\frac{21}{19} }}$

$\bold{[ \ Explanation \ ]}$

$\bold{Solve: \ f \ - \ 20f \ = \ 21}$

-----------------------------------

$\bold{Add \ Similar \ Elements:f-20f=-19f}$

$\bold{-19f=21}$

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3 years ago

Which expression is equivalent to 4(x+2)

Alekssandra [29.7K]

Answer:

$4x+8$

Step-by-step explanation:

We have been given an expression $4(x+2)$ . We are asked to find equivalent expression to our given expression.

Using distributive property $a(b+c)=ab+ac$ , we will get:

$4\cdot x+4\cdot2$

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Therefore, the expression $4x+8$ is equivalent to our given expression.

8 0

3 years ago

Read 2 more answers

A street magician asks a passerby to draw one card from a standard deck, remember it, and then replace it. The magician then shu

Romashka-Z-Leto [24]

Answer:

P( At least one of the two cards was a heart)=7/16

Step-by-step explanation:

The solution to this question can be found in two ways.

First way: Since total number of heart in a deck are four,

Probability that neither of two cards had a heart is that at both times the card drawn was not a heart, since it is an independent event, thus probability both were not heart= $\frac{3}{4}$ × $\frac{3}{4}$

= $\frac{9}{16}$

Thus, Probability that at least one of the two cards was a heart= 1- P( Neither of two cards had a heart= 1- $\frac{9}{16}$

= $\frac{7}{16}$

Second way:

Probability that first card drawn is a heart and the second one is not a heart= $\frac{1}{4}$ × $\frac{3}{4}$

= $\frac{3}{16}$

Probability that the first card drawn is not a heart and the second one is a heart= $\frac{3}{4}$ × $\frac{1}{4}$

= $\frac{3}{16}$

Probability that both cards drawn are hearts= $\frac{1}{4}$ × $\frac{1}{4}$

= $\frac{1}{16}$

Adding all these probabilities, we have the probability that at least one of the card drawn was heart= $\frac{7}{16}$

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3 years ago