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2 years ago

Can someone help me with this?

Mathematics

1 answer:

kozerog [31]2 years ago

8 0

Answer:

204 in²

Given:

Base: 17 inch

Height: 24 inch

Area of Triangle:

1/2 * Base * Height

1/2 * 17 * 24

1/2 * 408

204 in²

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A total of 17,100 seats are still available for the next hockey game. If 62% of the tickets are sold, how many seats are in the

MrRa [10]

Answer:

We have

seats x ( 62 / 100 ) = (seats - 17,100);

seats x 62 = 100 x (seats - 17,100);

seats x 62 = seats x 100 - 1710000;

1,710,000 = seats x 38;

seats = 1,710,000 ÷ 38;

seats = 45,000;

The correct answer is c. 45,000 seats;

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

5. Rory is playing a video game where each game lasts 13⁄4 hours. He wants to play for 9 hours today and this evening. How many

olga_2 [115]

He can play two games. 13/4=3.25
3.25*2=6.5

7 0

4 years ago

It has rained 3/5 inch in 1/4 hour. If it continues to rain at the same rate,how much rain would fall in an hour

Scorpion4ik [409]

Answer:

2 2/5 inches

Step-by-step explanation:

3/5 x 4

3/5 x 4/1

3/5 x 4/1 = 12/5

12/5 = 2 2/5

5 0

3 years ago

Kayden is buying bagels for a family gathering. Each bagel costs $1.50. Answer the questions below regarding the relationship be

Anna11 [10]

Answer:

y= $1.50x

Step-by-step explanation:

Each bagel is $1.50,therefore for each family member(x) the amount increaes by the same rate

4 0

3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

4 0

3 years ago