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Crazy boy [7]
2 years ago
13

what are the three strategies that the community could place to work with governmental structures to stop illegal dumping​

Biology
1 answer:
PtichkaEL [24]2 years ago
6 0

Answer:

Illegal Dumping has gotten out of hand.  According to the Los Angeles County Public Works, “People usually dump illegally to avoid collection and disposal fees, or because they believe proper disposal is just ‘too much trouble’.”   This is very unfortunate for our communities who receive the negative consequences of higher taxes for cleanup, environmental hazards, and a breeding ground for rats.

The cost of a one-time cleanup and detoxing of an area can cost thousands of dollars.  But to leave the mess is just not an option.  The best option is to stop the illegal dumping before it happens, preventing the cost of cleanup, preventing the chemicals and toxins from entering the ground water, and preventing the rats and mosquitoes from breeding.  The best areas to live are communities that care about their community!  So, what can a community do to prevent illegal dumping?

Here are some key points to help deter illegal dumping:

Educate the public through the schools and through community awareness groups about the costs, chemical hazards and dangers incurred by illegal dumping

Create safe, public-friendly waste disposal options and advertise them

Create laws that impose stiff fines for the perpetrators and advertise these stiff fines

Use Illegal Dumping Cameras to catch the perpetrators in the act

Use Social Media to ask the public to identify the perpetrators

Follow through with quick clean up

These steps will invite the citizens to be involved and help deter the criminal activity of illegal dumping within your community.

Tags: Deter Illegal Dumping, How to stop illegal dumping, illegal dumping, Illegal Dumping - disease, Illegal dumping camera, Illegal Dumping is harmful, illegal dumping prevention, Illegal dumping problems, illegal dumping solution, illegal dumping- tires, illegal waste

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1. Answer: 900x

A typical microscope has two lens: ocular lens which located near the eye, and objective lens which located near the object. The image will undergo magnification of both lens. The total magnification of the object would be the product of both lens multiplication, not the sum. The multiplication will be: 20x * 45x= 900x

total mag= ocular * object

total mag= 20x * 45x

total mag= 900x


2.  Answer: 100x

The total magnification of the object would be the product of both lens multiplication. If the total magnification 1000x, that mean it was the product of ocular lens and objective lens. If ocular lens magnification is 10x, objective lens magnification would be:

total mag= ocular * object

1000x= 10x*object

object=1000x/ 10x=

object=100x

3. Answer: 0.2 mm

The area of the microscope that can be viewed by the eye should be the same. But since the magnification is different, the actual area that it represent will be different. Microscope with bigger magnification will have smaller diameter of the field of view(DFV).  Remember that micrometer(μm) is 1/1000 of millimeter(mm). The DFV would be:500 μm/ ( 1000x/400x)= 200μm= 0.2 mm


4. Answer: 750μm

This question is similar to number 3 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm) .

The DFV of a 10x objective lens is 3 mm. Then the DFV of 40x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 3mm/ ( 40x/10x)= 0.75 mm= 750μm

5. Answer: 125μm x 37.5μm

The lens DFV of microscope from question 4 is 750μm, so the width and length of the area would be 750μm.

If 6 organisms could fit across the DFV if they were laid end-to-end, the length would be: 750μm/ 6 organism= 125μm

If 20 organism could fit is stacked side by-side, then the width would be: 750μm/ 20 organism= 37.5μm

6. Answer: 6mm

This question is similar to number 3 and number 4 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm).

The DFV of a 100x objective lens is 1.5 mm. Then the DFV of 25x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 1.5mm/ (100x/25x)= 6 mm


7.Using the 100x objective lens from question 6, you estimate 12 organisms could fit across the DFV if they were laid end-to-end and 30 could fit is stacked side-by-side. What is the length and width of this organism (in microns)?  

Answer: 0.5mm x 0.2mm or 500μm x 200μm

The lens DFV of microscope from question 6 is 6 mm, so the width and length of the area would be 6 mm.

If 12 organisms could fit across the DFV if they were laid end-to-end, the length would be: 6mm/ 12 organism=0.5mm

If 30 organism could fit is stacked side by-side, then the width would be: 6mm/ 30 organism= 0.2mm

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Answer;

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Explanation;

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Explanation:

Electrons are negatively charged particles found in atoms. These different from protons and neutrons are not located in the nucleus of the atom but orbit it. Additionally, electrons do not orbit the nucleus following a linear pattern but they have a wave-like behavior which means they move in a three-dimensional space or area known as electron orbital in which they can be found most of the time, this space of area is determined depending on energy, momentum, and other factors. Thus, an electron orbital is "a three-dimensional space where an electron can be found 90% of the time".

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