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docker41 [41]
3 years ago
11

What is the solution to this equation?

Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0

Answer:

x=25

Step-by-step explanation:

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f(\frac{1}{2} )=\frac{14}{3}

Step-by-step explanation:

Substitute 1/2 wherever you see x

f(\frac{1}{2} ) = \frac{-2}{3} (\frac{1}{2}) + 5\\

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a soft drink vendor at a popular beach analyzes his sales recods and finds that if he sells x cans of soda pop in one day, his p
ZanzabumX [31]

Complete Question:

A soft-drink vendor at a popular beach analyzes his sales records, and finds that if he sells x cans of soda pop in one day, his profit (in dollars) is given by P(x) = -0.001x² + 3x - 1800.

a. What is his maximum profit per day?

b. How many cans must be sold in order to obtain the maximum profit?

Answer:

a. $450

b. 1500 cans

Step-by-step explanation:

Given the following quadratic function;

P(x) = -0.001x² + 3x - 1800  ......equation 1

a. To find his maximum profit per day;

Since P(x) is a quadratic equation, P(x) would be maximum when x = \frac {-b}{2a}

Note : the standard form of a quadratic equation is ax² + bx + c = 0  ......equation 2

Comparing eqn 1 and eqn 2, we have;

a = -0.001, b = 3 and c = -1800

Now, we determine the maximum profit;

x = \frac {-b}{2a}

Substituting the values, we have;

x = \frac {-3}{2*(-0.001)}

Cancelling out the negative signs, we have;

x = \frac {3}{2*0.001}

x = \frac {3}{0.002}

x at maximum = 1500

Substituting the value of "x" into equation 1;

P(1500) = -0.001 * 1500² + 3(1500) - 1800

P(1500) = -0.001 * 2250000 + 4500 - 1800

P(1500) = -2250 + 2700

P(1500) = $450

b. Therefore, the soft-drink vendor must sell 1500 cans in order to obtain the maximum profit.

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3 years ago
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