9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
__
1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
Answer:
<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>
Step-by-step explanation:
Given the expression 
To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;
Then we find the LCM of the resulting function
The final expression gives the required answer
Answer:
n = 4752 gallons
Step-by-step explanation:
Given
Dilivery: 396 dozen gallon in a day
RequirEd
determine the number of the gallon in a day
we understand that:
n= 396 dozen
unit conversion
1 dozen = 12
so
n = 396 dozen gallon
n = 396× 12
n = 4752 gallons
hence 4752 gallons milk is delivered daily
5/8 * 4/5
= 1/8 * 4/1
= 1/4 * 2/1
1/2 * 1/1
Final answer = 1/2
It is division and a good technique is adding it like 8 x 6 = ? So I added 8+8+8+8+8+8 and there's my answer 48
