Let m and r represent the maximum speeds of Malcolm and Ravi in km/h, respectively.
... (m + r)/2 = 260 . . . . . the average of their speeds was 260 kph
... 2m = r + 80 . . . . . . . . double Malcolm's speed is 80 kph more than Ravi's
The second equation can be solved for r and that expression substituted into the first equation.
... 2m - 80 = r . . . . . . . . . . . an expression for r from the second equation
... (m + 2m - 80)/2 = 260 . . . the result of substituting that into the first
... 3m - 80 = 520 . . . . . . . . multiply by 2
... m = 200 . . . . . . . . . . . . . add 80 and divide by 3
... 2·200 - 80 = r = 320 . . .substitute the value of m into the expression for r
Malcolm's maximum speed was 200 km/h.
Ravi's maximum speed was 320 km/h.
Hope this helps
1.$40
2.$42.80
3.$51.36
2L + 2W = 36
2(3+2W) + 2W = 36
6 + 4W + 2W = 36
6W + 6 = 36
-6 = -6
6W=30
W= 30/6 = 5 L= 3 + 2W = 3 +2 (5) = 3 +10= 13
Width is 5
Length is 13
Hello from MrBillDoesMath!
Answer:
(x+2) ( x^2 + 3)
Discussion:
x^3 + 2x^2 + 3x + 6 =
(
x^3 + 2x^2) + (3x + 6) = => factor "x^2" from the first term; factor 3
from the second term
x^2( x + 2) + 3( x+2) = => factor (x+2) from each term
(x+2) ( x^2 + 3)
Thank you,
MrB
You must mean the depth of the submarine.
to make sum = zero the depth of the sub must be -1600 ft..
