Question

What are the solutions to (m +11)2 = 64?

Answer 1

Answer:

(21 + 11)2 = 64

So, I don't think teachers do this, but this is my way of doing it

Okay, so first, I divided 64 by 2 :

64 ÷ 2 = 32

Then, I subtracted 11 from 32:

21

Now, to check, just do the problem :

(21 + 11)2 = 64

      32 * 2 = 64

Answer 2

Answer:

The solutions are:

$m=-3,\:m=-19$

Step-by-step explanation:

Given the expression

$\left(m\:+11\right)^2=\:64$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

solving

$m+11=\sqrt{64}$

$m+11=\sqrt{8^2}$

$m+11=8$        ∵ $\sqrt{8^2}=8$

Subtract 11 from both sides

$m+11-11=8-11$

Simplify

$m=-3$

now solving

$m+11=-\sqrt{64}$

$m+11=-\sqrt{8^2}$

$m+11=-8$      ∵ $\sqrt{8^2}=8$

Subtract 11 from both sides

$m+11-11=-8-11$    

Simplify

$m=-19$

Thus, the solutions are:

$m=-3,\:m=-19$