U will get brainliest and all my points

A line passes through the point (-8, 3) and has a slope of 3/4. Write an equation in slope-intercept form for this line.

agasfer [191]

General formula to make slope-intercept form
y - y₁ = m(x - x₁)

From the question, we know that
m = 3/4
(x₁,y₁) = (-8,3)

Put the number to the formula
y - y₁ = m(x - x₁)
y - 3 = 3/4(x - (-8))
y - 3 = 3/4(x + 8)
y - 3 = (3/4)x + 6
y = (3/4)x + 9

6 0

4 years ago

Jenna manipulated the equation 4x + 7=10 by adding -7 to both sides.Which of the follolwing properties justifies this manipulati

elena-14-01-66 [18.8K]

The addition property of equality justifies this. You could also say that she simply subtracted 7, and then it would be the subtraction property of equality. This is the case because if you add or subtract (or multiply or divide) the same number on both sides of an equation, the equation will still be the same.

Hope it helps!

5 0

3 years ago

Does 2 and 12 have a least common multiple of 24

vova2212 [387]

Answer:

Least common multiple (LCM) of 12 and 24 is 24.

Step-by-step explanation:

6 0

3 years ago

mariarad [96]

Answer:

$p_v =P(z>2.087) =0.0184$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

$\sigma=2.5$

And the statistic is given by this formula:

$z=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sigma\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}$

Where z follows a normal standard distribution

The system of hypothesis on this case are:

Null hypothesis: $\mu_c \leq \mu_t+1$

Alternative hypothesis: $\mu_c >\mu_t+1$

Or equivalently:

Null hypothesis: $\mu_c - \mu_t \leq 1$

Alternative hypothesis: $\mu_c-\mu_t>1$

Our notation on this case :

$n_c =45$ represent the sample size for group control

$n_t =45$ represent the sample size for group treatment

$\bar X_c =5.2$ represent the sample mean for the group control

$\bar X_t =3.1$ represent the sample mean for the group treatment

And now we can calculate the statistic:

$z=\frac{(5.2-3.1)-(1)}{2.5\sqrt{\frac{1}{45}}+\frac{1}{45}}=2.087$

And now we can calculate the p value using the alternative hypothesis:

$p_v =P(z>2.087) =0.0184$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.

5 0

3 years ago

Scott works on cars. He charges $35 for each car plus $13 per hour. Yesterday he worked for 5 hours on 3 different cars. How muc

Mashcka [7]

Answer:

170

Step-by-step explanation:

35 x 3cars= 105 13 x 5hours= 65 105+65= $170

7 0

3 years ago

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