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2 years ago

Answer plz for brainliest

Mathematics

1 answer:

kobusy [5.1K]2 years ago

8 0

Answer:

7 units

Step-by-step explanation:

Please refer to the image attached with this answer.

Our initial line was CD joining points (-1,2) and (6,2).

It is now pulled down by 4 units , to new points

(-1,-2) and (6,-2)

Now we again shift this line by 2 units to the left. The new coordinates thus would be C'(-3,-2) and D'(4,-2)

Hence the distance C'D' = 4-(-3) = 4+3 = 7 UNITS

Hence the length of the line will be 7 units.

It is observed that the length of the line segment remains the same as it was of the original line. as the translation is uniform.

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Compare adding unlike fractions and adding like fractions

muminat

Answer:

We just add numerators and rewrite denominator.

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

Step-by-step explanation:

You mean unlike denominators and like denominators.

Adding like dominators: We just add numerators and rewrite denominator :

Example : $\frac{1}{4} +\frac{2}{4}=\frac{1+2}{4} =\frac{3}{4}$

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

For example :

$\frac{1}{5}+\frac{3}{4}$

LCM for 5 and 4 is 20 : Now, divide by 5 and multiply by 1 for first fraction. 20 divide by 4 and multiply by 3 :

$\frac{1*4}{20} +\frac{3*5}{20}=\frac{4}{20} +\frac{15}{20}=\frac{19}{20}$

4 0

3 years ago

Read 2 more answers

5 fifths × 3 fifteinths =?

Pachacha [2.7K]

Answer:

1/5 or 0.2 i hope this helped you

8 0

2 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$