Answer:
a) D = 4.88 * 10^(-14) m^2 / s
b) <em>t </em>= 1.1 hr
Solution:
a) Magnesium in Aluminum diffusion:
D = Do * exp(-Qd / RT)
= (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)
= 4.88 * 10^(-14) m^2 / s
D = 4.88 * 10^(-14) m^2 / s
b) The composition remains same at say the distance Xo:
(Cx - Co) / (Cs - Co) = Constant
Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15
D_{550} * <em>t </em>= D_{450} * 15
(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>
(4.88 * 10^(-14) m^2 / s) * 15
by, solving for <em>t </em>we get:
<em>t </em>= 1.1 hr
So, the time required is 1.1 hr.
The camera that <span>is a high-end digital camera that has interchangeable lenses and uses a mirror to display on its screen an exact replica of the image to be photographed is called an SLR. Hope this answers the question. Have a nice day.</span>
Answer: CIC
Explanation:
A call center is a customer interaction center (CIC) and it is the interface between call center agent with the customers directly. CIC are connected by the external telephone system and it uses as call center.
And the caller are basically identify by the telephone number and customer information are display in the CIC.
CIC are the modular structure for communication which include various components of CIC and framework.
Hi! Did you forget to add something to this?
Answer:
The correct option is;
Selecting the correct browser to use for the sites you want to visit
Explanation:
Censorship of information is the subduing of information based on the consideration of such information being harmful or inconvenient
Increased anonymity
Making an individual anonymous which is one of the capabilities of the internet, is seen as encouraging unethical behavior and promoting discussions which are deemed uncivil in a commonly shared space online.
Unauthorized sharing of copyrighted information
The sharing and distribution of copyrighted material is against the law but it is a common occurrence and in various formats online
Out of the given options, selecting the correct browser to use for the sites you want to visit is the one that is not a concern.
