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laila [671]
3 years ago
14

On a Windows network share, if the user can add, edit, and delete files and folders within the LabFiles folder, what type of acc

ess controls and permissions are probably configured?
Computers and Technology
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

Modify

Explanation:

When people like your family or friends can access a computer, then the need to have permissions would certainly come in handy. There are six basic types of permission one can choose from and the modify option is one of them. It simply grants the holder the ability to read and write files and subfolders and also allows for the deletion of folders and files.

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Help me<br>please answers this questions<br>​
kobusy [5.1K]

Answer:

RSI stands for repeating similar movements

3 0
2 years ago
Using Module operator, write a java program to print odd number between 0 and 1000​
jolli1 [7]

Answer:

class OddNumber

{

  public static void main(String args[])  

       {

         int n = 1000;  //Store 1000 in Variable n typed integer

         System.out.print("Odd Numbers from 1 to 1000 are:");  // Print headline of output window

         for (int i = 1; i <= n; i++)  //For loop to go through each number till end

          {

            if (i % 2 != 0)  //check if number is even or odd.Not divisible by 2 without reminder means it is odd number

             {

               System.out.print(i + " "); //print odd numbers

             }

          }

       }

}              

5 0
3 years ago
Which slot type would you install a video card in to get the best performance?
erma4kov [3.2K]
It really is hard to say because there are many slots and we do not know what your teacher is teaching. I have seen a lot of teachers teaching out of date material. With that said, here is a list from best to worst.

PCI Express x16
PCI Express x1
AGP
PCI

This is list is based on greatest to least and base on the bandwidth read and write speed.

6 0
3 years ago
____ is an easy way to invitation through a web page​
madreJ [45]

Correct Question:

_______ is an easy way to navigate through a web page. ​

Answer:

Scrolling.

Explanation:

The responsiveness of a webpage is an ability of the design to respond to the end user's digital device and screen size.

In Computer programming, a responsive web design makes it possible for various websites to change layouts in accordance with the user's digital device and screen size.

This ultimately implies that, a responsive design is a strategic approach which enables websites to display or render properly with respect to the digital device and screen size of the user.

Additionally, media queries are simple filter design that can be applied to cascaded style sheets(css).

Depending on the size of the viewport, media queries makes it easy to tweak styles depending on parameters such as width, orientation, height, resolution and display type of the device rendering the data

Hence, scrolling is an easy way to navigate through a web page. It avails the end users an ability to scroll (navigate) from side to side (left-right or right-left) and top to bottom (bottom-top) by using the horizontal and vertical onscreen scrollbars respectively.

3 0
3 years ago
2. Write a simple program in C++ to investigate the safety of its enumeration types. Include at least 10 different operations on
erastovalidia [21]

Answer:

Check the explanation

Explanation:

To solve the question above, we will be doing some arithmetic and bit wise operations on enum values. in addition to that, we are asserting the array with INTCOUNT  and also printing the size of array i.e 12 and we are adding BIG_COUNT enum value to 5 and the result is 25.

#include<stdio.h>

enum EnumBits

{

ONE = 1,

TWO = 2,

FOUR = 4,

EIGHT = 8

};

enum Randoms

{

BIG_COUNT = 20,

INTCOUNT = 3

};

int main()

{

// Basic Mathimatical operations

printf("%d\n",(ONE + TWO)); //addition

printf("%d\n",(FOUR - TWO)); //subtraction

printf("%d\n",(TWO * EIGHT)); //multiplication

printf("%d\n",(EIGHT / TWO)); //division

// Some bitwise operations

printf("%d\n",(ONE | TWO)); //bitwise OR

printf("%d\n",(TWO & FOUR)); //bitwise AND

printf("%d\n",(TWO ^ EIGHT)); //bitwise XOR

printf("%d\n",(EIGHT << 1)); //left shift operator

printf("%d\n",(EIGHT >> 1)); //right shift operator

// Initialize an array based upon an enum value

int intArray[INTCOUNT]; // declaring array

// Have a value initialized be initialized to a static value plus

int someVal = 5 + BIG_COUNT; //adding constant and BIG_COUNT variable

printf("%d\n",someVal); //value will be 25

printf("%d",sizeof(intArray)); //value will be 12

return 0;

}

Kindly check the attached image below for the Code and Output Screenshots:

6 0
3 years ago
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