All categories

3 years ago

True or False?

Mathematics

2 answers:

Annette [7]3 years ago

6 0

True because the 8 meters can be split up in 2 qnd

valentina_108 [34]3 years ago

4 0

I think it’s true, but I’m not 100% sure

You might be interested in

Proportions in Triangles

alukav5142 [94]

Answer:

x =35.

Step-by-step explanation:

x / 20 = 14 / 8

Cross multiply:

8x = 20*14

8x = 280

x = 35.

3 0

3 years ago

Ernesto Montenegro purchase a twelve 1000 Bonds having a quoted price of 100.75 he have to pay a 6% brokerage fee of the same pr

LenKa [72]

Answer: $106.8

Step-by-step explanation:

Given that the bond price is $100.75

With a 6% brokerage fee

Find the total cost to the nearest cent

First, we calculate the 6% brokerage fee= 6/100 × 100.75

= 0.06 x 100.75

= 6.045

Total cost therefore is the sum of brokerage fee and the cost of bond

= $6.045 + $100.75

= $106.795

To the nearest cent = $106.8

5 0

3 years ago

Pls helppppppppppppppppppppp

Julli [10]

Answer:

10 2/3

Step-by-step explanation:

Multiply 4 and 2 and then multiply 2 and 4. If you do that then you get 8 8/3. You then just take the numerator and turn it into whole numbers to get 10 2/3.

4 0

3 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

$P(X >300 ) = 0.97219$

8 0

3 years ago

bulgar [2K]

Answer:

8/9 will be left over

Step-by-step explanation:

3 7/9 + 5 1/3= 9 1/9

Now subtract the amount of paint needed by how much paint there is:

10- 9 1/9= 8/9

Therefore, 8/9 will be left over

Hope this helps

5 0

2 years ago