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2 years ago

Help !!! what are the coordinates of the vertices in the image ???

Mathematics

1 answer:

liq [111]2 years ago

6 0

Answer:

the coordinates are-

(3,3)

(0,5)

(0,3)

thenks and mark me brainliestt :))

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Solve for y:<br>5(x + y) = 20 + 3x

son4ous [18]

5(x+y)= 20+ 3x
5x+5y=20+3x
5x+5y-3x=20+3x-3x
2x+5y=20
2x+5y-2x=20-2x
5y=-2x+20
5y/5=-2x/5+20/5
y=-2/5x+4

ANSWER: y=-2/5x+4

5 0

3 years ago

Read 2 more answers

if you deposit 4500 at 5% annual interest compounded annually how much money will be in the account after 30 months

Alja [10]

Answer:

A = $ 50,978.44

Step-by-step explanation:

First, convert R percent to r a decimal

r = R/100

r = 5%/100

r = 0.05 per year,

Then, solve our equation for A

A = P(1 + r/n)nt

A = 45,000.00(1 + 0.004166667/12)(12)(2.5)

A = $ 50,978.44

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3 years ago

If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?2

aivan3 [116]

The second equation because they all have a common factor of 3. You can get x by itself. However, with the first one, you'll end up with fractions instead.

8 0

3 years ago

Josh lives one for 6 miles from the park so far he walked 2/3 of the distance from his house to the park how many miles has josh

Naily [24]

Answer:

Step-by-step explanation:

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3 years ago

A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r

Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

$P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5$

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, $n(S)=6$

Now, probability of rolling a 3 is given as:

$P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}$

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

$P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083$

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0

3 years ago