Answer:
The Proof is given below.
Step-by-step explanation:
Given:
P is the center of Circle
∠ONE ≅ ∠TEN
To Prove:
∠5 ≅ ∠6
Proof:
Exterior Angle Theorem:
Exterior Angle Property of a Triangle states that measure of exterior angle of a triangle is equals to the sum of measures of its interior opposite angles.
STATEMENT REASON
1. So In ΔONE,
1. Exterior Angle Property of a Triangle.
2. Similarly In ΔTEN,
2. Exterior Angle Property of a Triangle.
3. But , ∠ONE ≅ ∠TEN 3. Given
4. And P is the center of circle So
4.radius of same circle
5. ΔPEN is an Isosceles triangle,
∴ ∠ 1 ≅ ∠ 2 5. Isosceles triangle property
6. ∴ ∠5 ≅ ∠6 6. From 3 and 5 Transitive Property.........Proved
if I'm correct, 3 would be 78 as well . I'm so sorry if I get this wrong . I struggled a bit with this part and math a lot , and I only worked on it for like 2 days and then I had to test for it
-5(x – 3) = x + 27
multiply the bracket by -5
(-5)(x)=-5x
(-5)(-3)=15
-5x+15=x+27
Move +15 to the other side. Sign changes from +15 to -15.
-5x+15-15=x+27-15
-5x=x+27-15
-5x=x+12
Move +x to the other side. Sign changes from +x to -x.
-5x-x=x-x+12
-6x=12
Divide both sides by -6
-6x/-6=12/-6
Answer: x=-2