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Ber [7]
3 years ago
12

The probability that Tina makes a free throw in basketball is 11 percent. If she shoots 94 free throws tonight, how many should

she expect to make?
Mathematics
1 answer:
Tanzania [10]3 years ago
4 0
To answer this problem you should set up and proportion.

\frac{11}{100}=\frac{x}{94}

Then to solve it, you would cross multiply.

11*94=100*x
1034=100x
10.34=x

Your answer is 10.34.















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What value of x will make triangles ABM and DCM<br> congruent?<br> 3<br> 5<br> 7<br> 9
kykrilka [37]
The congruent side is going to be 9
6 0
2 years ago
List the angles in triangle QRS from smallest to largest.
schepotkina [342]

Answer:

angle R

Step-by-step explanation:

To solve this we will use cosine rule

Cosine rule

cos(A) = \frac{b^{2}+c^{2}-a^{2}}{2bc}

suppose,

q = 6.25

s = 11.04

r = 13.19

angleQ = cos^{-1}(\frac{13.19^{2}+11.04^{2}-6.52^{2}}{2(13.19)(11.04)})

            = 30.58

angleR = cos^{-1}(\frac{6.52^{2}+11.04^{2}-13.19^{2}}{2(6.52)(11.04)})

            = 93.82

angleS =  cos^{-1}(\frac{6.52^{2}+13.19^{2}-11.04^{2}}{2(6.52)(13.19)})

            = 56.63

4 0
3 years ago
Find sin (A-B) if sin A = 4/5 with A between 90 and 180 and if cos B = 3/5 with B between 0 and 90
quester [9]

Answer:

sin(A-B) = 24/25

Step-by-step explanation:

The trig identity for the differnce of angles tells you ...

sin(A -B) = sin(A)cos(B) -sin(B)cos(A)

We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.

And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.

Then ...

sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25

The desired sine is 24/25.

3 0
3 years ago
V-3/-10= -4 please answer step by step
Triss [41]

See the pic above!

Hope it helps!

5 0
3 years ago
A fertilizer covers 5/8 square foot in 1/4 hour
dybincka [34]
It takes about 15 minutes to cover 5/8²
5 0
3 years ago
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