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pantera1 [17]
2 years ago
7

Please help. 2) Find the measure of 2q in the figure.

Mathematics
2 answers:
aev [14]2 years ago
8 0
Q is 50 then subtract 130 from 18p
IRINA_888 [86]2 years ago
7 0
Q is 50. You subtract 130 from 180
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in a proportional relationship the ratio y/x is constant. Show that this ratio is not constant for the equation y=a-14
Colt1911 [192]

To show that the ratio \frac{y}{x} is not constant for the function y=a-14 we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here a represents x.  

To find the counter examples here, I will use the values a=20  and a=28. For a = 20 , the equation tells us that the output is

y=20-14=6. For this value of a the point is point is (20,6). The ratio \frac{y}{x} =\frac{6}{20}. For the a=28, y=28-14=14. For this value of a the  point is (28,14) . The ratio \frac{y}{x} =\frac{14}{28} =\frac{1}{2}. Clearly this ratio is not constant for all ordered pairs.

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2 years ago
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Answer: 12

Step-by-step explanation:

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Which expression is equivalent to -9x^-1y^-9/-15x^5y^-3? Assume x is not equal to 0,y is not equal to 0
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