The question describes a binomial probability with p(h) = p, then p(t) = 1 - p and number of trials (n) = 20
The probability of a binomial distribution is given by
Part A:
The probability of observing 8 heads and 12 tails is given by:
Part B:
<span>You observe more than 8 heads and more than 8 tails, when you observe 9 heads and 11 tails, 10 heads and 10 tails, and 11 heads and 9 tails.
Therefore, the probability of </span><span>observing more than 8 heads and more than 8 tails</span> is given by:
When you want to find a percent of a number you do this:
given number/ 1 multiplied by percentage/100
so in this question its a multiple step
start with finding 25 percent of 4250 which is= 1062.5
so thats how much the discount is so the amount after the 25% discount is:
4250-1062.5= 3187.5
then you have to add 9% due to fees
so you find 9% of 3187.5 which is= 286.875
so you add 286.875 to 3187.5 gives you= 3437.375 in total cost for the vacation package
Answer:
c
Step-by-step explanation:
The red graph is the black graph translated vertically by 1 unit
Given f(x) then f(x) + c is a vertical translation of f(x)
• If c > 0 then a shift up of c units
• If c < 0 then a shift down of c units
Thus f(x) + 1
Note
y - 1 = f(x) ← add 1 to both sides
y = f(x) + 1 ← as required
The equation of the red graph is
y - 1 = f(x) → c
Answer:
A) Distance time graph
B) d(t) = 25t
C) The expression shows the distance more clearly.
Step-by-step explanation:
A) A distance time graph as seen in the attachment provides a representation of the distance travelled.
We are told the car travels at a constant speed of 100 meters per 4 seconds. Which means that 100 m for each 4 hours. So, for 200m, it's 8 hours like seen in the graph and for 300m,it's 12 hours as seen in the graph.
B) And expression for the distance is;
d = vt
Where;
d is distance in metres
v is speed in m/s and t is time
We are told that the car travels at a constant speed of 100 meters per 4 seconds.
Thus, v = 100/4 = 25 m/s
Distance travelled over time is;
d(t) = 25t
C) Looking at both A and B above, it's obvious that the expression of the distance shows a more clearer way of getting the distance because once we know the time travelled, we will just plug it into the equation and get the distance. Whereas, for the representation form, one will need to longer graphs if the time spent is very long.
