Your answer to this is :
<h2>
C. Stretching.</h2>
<h2>→ <u>Explanation:-</u></h2>
<u />
Because the other one is congruent together.
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<em>Jaceysan ~</em>
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Answer:
(C) 
Step-by-step explanation:
Answer:
10\pi[/tex]
Step-by-step explanation:
Circunferencia de un círculo = Pi veces diámetro
como el diámetro es igual a la mitad del radio, sabemos que si multiplicamos el radio por dos obtendremos el diámetro del círculo. Por lo tanto, 5 veces 2 = 10. Ahora hacemos 10 veces pi. El cual es 10 pi o 31.4159
Circumference of a circle = Pi times diameter
since the diameter is equal to half the radius, we know that if we multiply the radius by two we will obtain the diameter of the circle. Therefore, 5 times 2 = 10. Now we do 10 times pi. Which is 10 pi or 31.4159
Answer: i'm not sure i wrote the problem out correctly but if this helps please give me a thanks!
Step-by-step explanation:
