Question

A florist sells a bouquet of roses

Answer 1

Answer:

Bouquets of roses = 20

Bouquets of carnations = 08

Step-by-step explanation:

Let,

x be the bouquets of roses sold

y be the bouquets of carnations sold

According to given statement;

x + y = 28       Eqn 1

16x + 10y = 400     Eqn 2

Multiplying Eqn 1 by 16

16(x+y=28)

16x + 16y = 448    Eqn 3

Subtracting Eqn 2 from Eqn 3

(16x+16y)-(16x+10y) = 448 - 400

16x + 16y - 16x - 10y = 48

6y = 48

Dividing both sides by 6

$\frac{6y}{6}=\frac{48}{6}\\y=8$

Putting y=8 in Eqn 1

x + 8 = 28

x = 28 - 8

x= 20

Hence,

Bouquets of roses = 20

Bouquets of carnations = 08