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Vsevolod [243]
3 years ago
8

Pliz answer this question

Mathematics
1 answer:
irina1246 [14]3 years ago
7 0
Cent is by the hundred so one percent is 1/100 so .6%=6/1000
which can be reduced to 3/500
You might be interested in
A sample of 300 urban adult residents of a particular state revealed 65 who favored increasing the highway speed limit from 55 t
forsale [732]

Answer and explanation:

Null hypothesis(H0) says sentiment for increasing speed limit in the two populations is the same

Alternative hypothesis(Ha) says sentiment for increasing speed limit in the two populations is different

Where p1 is the first population proportion =65/297= 0.22

And p2 is the second population proportion = 78/189= 0.41

P= p1+p2/n1+n2= 65+78/297+189= 0.29

Hence H0= p1-p2=0

Ha=p1-p2≠0

Test statistic= p1-p2/√p(1-p) (1/n1+1/n2)

= 0.22-0.41/√0.29(1-0.29)(1/297+1/189)

= -4.49

Critical value at 95% significance level= 1.96( from tables)

We therefore reject null hypothesis as critical value is greater than test statistic

Therefore the sentiment for increasing speed limit in the two populations is different

b. at proportions of 0.24 and 0.40 for p1 and p2 respectively

Test statistic = 0.24-0.40/0.29(1-0.29)(1/297+1/189)

= -3.78

P value is 0.0002 at 0.05 significance level

Hence probability =0.4998

7 0
3 years ago
3. A fast food joint sells 5 boxes of chicken nuggets for $33.90. Another fast food joint sells 4 boxe:
mrs_skeptik [129]
33.90/5= 6.78 or 26.88/4= 6.72. The 4 boxes of chicken fingers has the cheaper unit price
3 0
3 years ago
3x^2-192=0<br><img src="https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20%20-%20192%20%3D%200" id="TexFormula1" title="3 {x}^{2}
Murljashka [212]
3x^2-192=0
3x^2=192
x^2=\frac{192}{3}
x=\pm \sqrt{64}
x=\pm 8

x=-8 and x=8 are the solutions

5 0
2 years ago
Read 2 more answers
The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen
vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.75

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X = 9) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X \geq 16) when n = 20

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897

P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339

P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669

P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211

P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

E(X) = np

In this question, we have n = 22

So

E(X) = 22*0.75 = 16.5

The closest integer to 16.5 is 17.

7 0
2 years ago
Jasmine wants to earn $2,000 in simple interest through a
Ierofanga [76]

Answer:

$10000

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

P = 2000 / ( 0.05 × 4 ) = 10000

P = $ 10,000.00

The principal required to

accumulate interest of $ 2,000.00

on a rate of 5% per year for 4 years is $ 10,000.00.

3 0
2 years ago
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