Question

Help pleaseeeeeeeeeeeeeeeeeee

Answer 1

Answer:

$Area = 98.2142857143$

$Perimeter = 39.2857142857$

Step-by-step explanation:

From the attachment, we have:

• 2 semicircles B and C
• 1 quarter circle CDE
• radius, r = 5cm

To calculate the total area of the figure, we have to calculate the areas of individual shapes, then add them together

For Semicircle B

$Area = \frac{\pi r^2}{2}$

Substitute 5 for radius (r)

$A_1 = \frac{\pi * 5^2}{2}$

$A_1 = \frac{\pi * 25}{2}$

$A_1 = \frac{25\pi}{2}$

For Semicircle C

$Area = \frac{\pi r^2}{2}$

Substitute 5 for radius (r)

$A_2= \frac{\pi * 5^2}{2}$

$A_2 = \frac{\pi * 25}{2}$

$A_2 = \frac{25\pi}{2}$

For Quarter circle DC

$Area = \frac{\pi r^2}{4}$

Substitute 5 for radius (r)

$A_3= \frac{\pi * 5^2}{4}$

$A_3= \frac{\pi * 25}{4}$

$A_3= \frac{25\pi}{4}$

The area of the shape is:

$Area = A_1 + A_2 +A_3$

$Area = \frac{25\pi}{2}+\frac{25\pi}{2}+\frac{25\pi}{4}$

Take LCM

$Area = \frac{50\pi+50\pi+25\pi}{4}$

$Area = \frac{125\pi}{4}$

Take

$\pi = \frac{22}{7}$

So, we have:

$Area = \frac{125}{4} * \frac{22}{7}$

$Area = \frac{125*22}{4*7}$

$Area = \frac{2750}{28}$

$Area = 98.2142857143$

To calculate the total perimeter of the figure, we have to calculate the circumference of individual shapes, then add them together

For Semicircle B

$Circumference = \pi r$

Substitute 5 for radius (r)

$C_1 = \pi * 5$

$C_1 = 5\pi$

For Semicircle C

$Circumference = \pi r$

Substitute 5 for radius (r)

$C_2 = \pi * 5$

$C_2 = 5\pi$

For Quarter circle DE

$Circumference = \frac{\pi r}{2}$

Substitute 5 for radius (r)

$C_3 = \frac{\pi * 5}{2}$

$C_3 = \frac{5\pi}{2}$

The perimeter of the shape is:

$Perimeter = C_1 + C_2 + C_3$

$Perimeter = 5\pi + 5\pi + \frac{5\pi}{2}$

Take LCM

$Perimeter = \frac{10\pi + 10\pi + 5\pi}{2}$

$Perimeter = \frac{25\pi}{2}$

Take

$\pi = \frac{22}{7}$

So, we have:

$Perimeter = \frac{25}{2} * \frac{22}{7}$

$Perimeter = \frac{25*22}{2*7}$

$Perimeter = \frac{550}{14}$

$Perimeter = 39.2857142857$